The rule of thumb for this kind of problem is that you must first determine the limiting variable in your situation. We know that for a single sandwich, 50 grams bread greatly exceeds the 9 grams of ham requirement. We also know that there will be a greater supply of ham since 1 kg is relatively close in amount to 1.2 kg. This means that we only need to look at the bread for calculation purposes. We can get the total number of sandwiches to be 1200 / 50 = 24 sandwiches.
54% of the time. 21 and 45 is 66. Two hours is 120. The you subtract
f(x) = 112 - kx
f(-3) = 112 - k(-3)
f(-3) = 112 - (-3k)
f(-3) = 112 + 3k
121 = 112 + 3k
- 112 - 112
9 = 3k
3 3
3 = k
