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Leno4ka [110]
3 years ago
6

Is this right i dont know

Mathematics
1 answer:
adell [148]3 years ago
5 0

Answer:

Yes! Great Job

Step-by-step explanation:

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Answer to the equation: <br> -3|a - 1| = -15
Charra [1.4K]
Hello,

-3|a-1|=-15
==>|a-1|=5
==>a-1=5 or -a+1=5
==>a=6 or a=-4
Sol={-4,6}
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4 years ago
A production supervisor at a major chemical company wishes to determine whether a new catalyst, catalyst XA-100, increases the m
zheka24 [161]

Answer:

a. n= 47

b. n= 128

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the new catalyst, XA-100, increases the mean hourly yield of a chemical process, that is known to be μ=750 (pounds per hour) with the current process.

You need to calculate the sample size to estimate the population with determined error margins.

To do so, since you have no population information, only that it is approximately normal distributed, you'll use the Student t statistic to get the sample size.

The formula of the margin of error (d) is:

d= t_{n-1: 1-\alpha/2} * (\frac{S}{\sqrt{n} })

I've  cleared the sample size of the formula

n= (S*\frac{t_{n-1; 1-\alpha /2} }{d} )^{2}

You need a sample size for the t-Student value and a standard deviation, that's why the information of a pilot study with n=5 and S= 19.62 is given.

a)

95% CI

d= 8 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.025}  = t_{4;0.975} =2.776

n= (19.62*\frac{2.776 }{8} )^{2}

n= 46.35 ≅ 47

b)

99% CI

d= 5 pounds

t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.005}  = t_{4;0.995} =4.604

n= (19.62*\frac{4.604}{8} )^{2}

n= 127.49 ≅ 128

I hope it helps!

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Yes I Belive so yeah
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