The equivalent expression is 5^(4) * 3^(-10)
<h3>How to determine the equivalent expression?</h3>
The statement is given as:
five raised to the negative second power times three raised to the fifth power end quantity all raised to the negative second power
Rewrite properly as:
(5^-2 * 3^5)^-2
Expand the expression by multiplying the exponents
So, we have:
5^(-2 -2) * 3^(5 *-2)
Evaluate the products
5^(4) * 3^(-10)
Hence, the equivalent expression is 5^(4) * 3^(-10)
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The system shown at the right has no solution, as the grahs never intersect.
On the other hand, the line and the parab. at the left do intersect, and the points of intersection are (-3,0) and (6,6).
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Answer:
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Answer: The answer is (2)
Just evaluate the functions with the values of the figure