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2 years ago

there are 12 students who play the clarinet and 16 students who play the viola. what does the ratio 16:12 describe?

1 answer:

6 0

Answer: The ratio 16:12 describes the ratio of the number of students who play the viola to the students who play the clarinet.

Step-by-step explanation:

Given : Number of students who play the clarinet= 12

Number of students who play the viola=16

We know that ratio of A to B is represented by A:B.

Since, the number '12' is representing " students who play the clarinet" and number '16' is representing " students who play the viola"

So , the ratio 16:12 describes the ratio of the number of students who play the viola to the students who play the clarinet.

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3 2/5+3 2/5/2 1/12 what is theeeeee answerrrr

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Answer:

the awnswer is 5.032\

Step-by-step explanation:

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2 years ago

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uppose a report stated the following: In a survey of more than 3000 people, 93% of the respondents claimed to prefer Isaac's Imm

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Answer:

A. People who are related to the employees of Isaac's Immaculate Ice Cream

Step-by-step explanation:

If the results are called into question, this means there is potential bias in the survey.

Randomly choosing people from a phone book or another random method would not create bias.

Having people blindly test brands of ice cream would not create bias, as it is random and fair.

However, if the people surveyed were related to employees of Isaac's Immaculate Ice Cream, the results could be called into question over a fear of favoritism.

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3 years ago

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In a recent study of 42 eighth graders, the mean number of hours per week that they watched television was 19.6. Assume the popu

olya-2409 [2.1K]

Answer:

$19.6-2.42\frac{5.8}{\sqrt{42}}=17.43$

$19.6+2.42\frac{5.8}{\sqrt{42}}=21.77$

And the best option for this case would be:

a. (17.5, 21.7)

Step-by-step explanation:

Information given

$\bar X= 19.6$ represent the sample mean

$\mu$ population mean

$\sigma= 5.8$ represent the population deviation

n=42 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom, given by:

$df=n-1=42-1=41$

Since the Confidence is 0.98 or 98%, the significance would be $\alpha=0.02$ and $\alpha/2 =0.1$ , and the critical value would be $t_{\alpha/2}=2.42$