Which equation has one solution? x^2= 1 X^2= -16 x² = 0 x² = 12
1 answer:
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A) the posible roots of the function f(x)=x⁴-3x³-5x²+21x+22 are:
=-1,+1,-2,+2,-11,+11,-22+22.
b)
one zero of the funtion can be: x=-1 ⇒y=0 (-1,0)
c)
other zero of the funtion is: x=-2 ⇒y=0 (-2,0)
d)
if x=0 then y=22 (0,22)
e) In the file is the graph.
=-1,+1,-2,+2,-11,+11,-22+22.
b)
one zero of the funtion can be: x=-1 ⇒y=0 (-1,0)
c)
other zero of the funtion is: x=-2 ⇒y=0 (-2,0)
d)
if x=0 then y=22 (0,22)
e) In the file is the graph.