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gladu [14]
2 years ago
13

what is the slope-intercept form for a line that has a slope of -4/5 and passes through points (0,7)?

Mathematics
1 answer:
drek231 [11]2 years ago
4 0

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{7})~\hspace{10em} slope = m\implies -\cfrac{4}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=-\cfrac{4}{5}(x-0) \\\\\\ y-7=-\cfrac{4}{5}x\implies y=-\cfrac{4}{5}x+7

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70 points and i’ll give brainliest!! please answer all the questions on the page! must show work and how you got the answer. ple
Bezzdna [24]

6. One variable only so pretty straightforward.

length-x+4

width-x

x+x+4=80

2x=76

x=38

x+4=42

answer: length 42cm and width 38cm

7. Another money problem!

n-# of nickels

q-# of quarters

n=3+q

0.05n+0.25q=2.85

Substitution works like a charm!

0.05(3+q)+0.25q=2.85

0.15+0.05q+0.25q=2.85

0.3q=2.7

q=9

n=3+q

n=3+9

n=12

answer: 9 nickels and 12 quarters

8. One variable situation again.

Ann's money-2b+9

Betty's money-b

b+2b+9=60

3b=51

b=17

2b+9=43

answer: Ann has $43 and Betty has $17.

9. # of red m&m's-x+1

# of blue m&m's-x

x+1+x=13

x=6

x+1=7

answer: 6 blue and 7 red m&m's

10. a-number of adult tickets

s-number of student tickets

a+s=785 ----> a=785-s

5a+2s=3280

5(785-s)+2s=3280

-3s=-645

s=215

a+s=785

a+215=785

a=570

answer: 215 children tickets and 570 adult tickets

3 0
3 years ago
SOLVE for me. All multiple choice
tester [92]

9: B right

10: C obtuse

11: B right

12: B right

I hope they are right! Sorry if they are not!

6 0
3 years ago
Hey guys!! Kon'nichiwa!!
mina [271]

Answer:

1. 1.79

2.11.486

3.2.3562

4.61.4

5. 115.7226

( 이게 옳은 거니?)

(;ŏ﹏ŏ)

6 0
2 years ago
Read 2 more answers
Matsuki is very very bored...<br><br> 34 + 35 x (60/2) - (40/2) = ?
allsm [11]

I believe the answer is 1064.

P.s. your cute matsuki <3

4 0
2 years ago
Can someone please explain how to get this answer? Recursive formula help!<br>t(1)=3 (in picture)
kipiarov [429]
T(1) = 3, t(n) = -2t(n-1) + 1
So t(2) = -2(t(1)) + 1 = -2(3) + 1 = -5
t(3) = -2(t(2)) +1 = -2(-5) +1 = 11
t(4) = -2(t(3)) +1 = -2(11) +1 = -21
t(5) = -2(t(4)) +1 = -2(-21) +1 = 43
3 0
2 years ago
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