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gladu [14]
2 years ago
13

what is the slope-intercept form for a line that has a slope of -4/5 and passes through points (0,7)?

Mathematics
1 answer:
drek231 [11]2 years ago
4 0

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{7})~\hspace{10em} slope = m\implies -\cfrac{4}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=-\cfrac{4}{5}(x-0) \\\\\\ y-7=-\cfrac{4}{5}x\implies y=-\cfrac{4}{5}x+7

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Answer:

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Step-by-step explanation:

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Line j has an equation of y - 8 = -2/3(x+5). Line K is perpendicular to line j and passes + through (-6, -2). What is the equati
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Answer:

y = \frac{3}{2} x + 7

Step-by-step explanation:

the equation of a line in point- slope form is

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given a line with slope m then the slope of a line perpendicular to it is

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