3 years ago

what is the slope-intercept form for a line that has a slope of -4/5 and passes through points (0,7)?

1 answer:

4 0

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{7})~\hspace{10em} slope = m\implies -\cfrac{4}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-7=-\cfrac{4}{5}(x-0) \\\\\\ y-7=-\cfrac{4}{5}x\implies y=-\cfrac{4}{5}x+7$

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❃Incase you forgot what the linear equation formula is ☟

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❃Incase you also forgot, The is what the slope formula is ☟

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➋Second: We find the y-intercept.

$y = mx + b \\ 0 = \frac{1}{3} (5) + b \\ 0 = \frac{5}{3} + b \\ \frac{ - \frac{5}{3} = - \frac{5}{3 } \: \: \: \: \: \: \: \: \: \: \: \: }{ - \frac{5}{3} = b}$