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mojhsa [17]
2 years ago
7

A submarine was located 200 feet below sea level. If it ascends 55 feet and then drops 87 feet, then which integer represents th

e new position of the submarine? Answer choices: -342 ft, -255 ft, -232 ft, 232 ft. Please tell me how you got the answer!!
Mathematics
2 answers:
kirill [66]2 years ago
6 0

Answer:

-232

Step-by-step explanation:

Masteriza [31]2 years ago
6 0
-232 ft i’m pretty sure:)
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Solve the equation 2x+1=x-3​
Agata [3.3K]

How to solve your problem

Topics: Algebra, Quadratic Equation

2

+

1

=

−

3

2x+1=x-3

2x+1=x−3

Solve

1

Subtract

1

1

1

from both sides of the equation

2

+

1

=

−

3

2x+1=x-3

2x+1=x−3

2

+

1

−

1

=

−

3

−

1

2x+1{\color{#c92786}{-1}}=x-3{\color{#c92786}{-1}}

2x+1−1=x−3−1

2

Simplify

Subtract the numbers

Subtract the numbers

2

=

−

4

2x=x-4

2x=x−4

3

Subtract

x

x

from both sides of the equation

2

=

−

4

2x=x-4

2x=x−4

2

−

=

−

4

−

2x{\color{#c92786}{-x}}=x-4{\color{#c92786}{-x}}

2x−x=x−4−x

4

Simplify

Combine like terms

Multiply by 1

Combine like terms

=

−

4

x=-4

x=−4

Solution

=

−

4

5 0
3 years ago
[Annie: 4 (x+y+z) Bradley: 4x+yz Carlos: 4xyz Zuri: 4x+4z+4y]
slega [8]
4x+4y+4z. I was taught to take out what was in each term, in this problem that would be 4: 4(X+y+z). Meaning A) Annie did the problem right :) I hope this helps!
8 0
3 years ago
Read 2 more answers
What is the greatest common factor of 24 30 and 42
Helen [10]
List the factors of 24,30, and 24. Factors of 24: 1,2,3,4,6,8,12,24. Factors of 30: 1,2,3,5,6,10,15,30. Factors of 42: 1,2,3,6,7,14,21,42. The highest number that all of these numbers is 6. Therefore, the greatest common factor of GCF of 24,30, and 42 is 6.
6 0
3 years ago
Read 2 more answers
What quadrants is the points (2,-3)?
zheka24 [161]

Answer:

Quadrant 4

there are four quantdrants, A is on the fourth one

4 0
2 years ago
The drama club collected $160 from ticket sales for the spring play. They need to collect at least $400 to pay for new lighting
valentina_108 [34]
We assume all money is spent on new lighting. Since they currently have $160 and need $400 we can subtract what they currently have from what they need.

$400-$160 = $240

Since we know the price of the ticket and now know they need $240 we can divide our $240 with the price of each ticket ($3)

$240/$3 = 80

So the drama club has to sell 80 more tickets in order to afford new lighting
6 0
2 years ago
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