. If CD = 4 and the perimeter of △ABC is 23, what is the perimeter of △ABE?
1 answer:
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Step-by-step explanation:
Hey there!!
Given,
Cross multiply.
15 = 2z
Therefore, z= 15/2
<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>
x = 0, x = , x = -
since we have a product of factors equal to zero, equate each factor to zero and solve for x
x² = 0 ⇒ x = 0 ( multiplicity 2 )
5x - 7 = 0 ⇒ x =
3x + 2 = 0 ⇒ x = -
Answer:
(-8,-10)
Step-by-step explanation:
Rewrite (x+8)2(x+8)² as (x+8)(x+8).
f(x)=3((x+8)(x+8))−10
Expand (x+8) (x+8) using the FOIL Method.
Apply the distributive property.
f(x)=3(x(x+8)+8(x+8))−10
Apply the distributive property.
f(x)=3(x⋅x+x⋅8+8(x+8))−10
Apply the distributive property.
Simplify and combine like terms.
Simplify each term.
Multiply x by x.
f(x)=3(x2+x⋅8+8x+8⋅8)−10
Move 8 to the left of x.
f(x)=3(x2+8⋅x+8x+8⋅8)−10
Multiply 8 by 8.
f(x)=3(x2+8x+8x+64)−10
Add 8x and 8x.
f(x)=3(x2+16x+64)−10
Apply the distributive property.
f(x)=3x2+3(16x)+3⋅64−10
Simplify.
Multiply 16 by 3.
f(x)=3x2+48x+3⋅64−10
Multiply 3 by 64.
f(x)=3x2+48x+192−10
Subtract 10 from 192.
f(x)=3x2+48x+182
The minimum of a quadratic function occurs at x= If a is positive, the minimum value of the function is f (
).
Substitute in the values of aa and b.
x=−
x=-8
Replace the variable x with −8 in the expression.
f(−8)=3(−8)2+48(−8)+182
Y=-10
Therefore, the minimum value is (-8,-10) but if it is asking for just the y-value it would be -10.