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2 years ago

. If CD = 4 and the perimeter of △ABC is 23, what is the perimeter of △ABE?

Mathematics

1 answer:

OlgaM077 [116]2 years ago

6 0

Answer:

Step-by-step explanation:

ABC has a perimeter of 23, so

AB + BC + AC = 23

The perimeter of ABE would be the sum of these sides:

AB + BC + CD + DE + AE

We also know:

AE = AC, CD=4 and DE=4 because ACD is congruent to AED

So, AB + BC + CD + DE + AE = AB + BC + 4 + 4+ AC = 23+8 = 31

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There are two numbers, one is 7 more than twice the other. The sum of the numbers is 43. Make the equation to find the smaller n

Mrrafil [7]

Answer:

Smaller number: 12

Greater number: 31

Step-by-step explanation:

Hi there!

Let x equal to the smaller number.

Let y be equal to the greater number.

1) Translate the information into equations

"One is 7 more than twice the other"

⇒ $y=2x+7$

"The sum of the numbers is 43"

⇒ $x+y=43$

2) Use substitution to solve for the smaller number

$x+y=43$

Plug the equation $y=2x+7$ into the above equation

$x+(2x+7)=43\\x+2x+7=43\\3x+7=43$

Subtract both sides by 7

$3x+7-7=43-7\\3x=36$

Divide both sides by 3 to isolate x

$\frac{3x}{3} = \frac{36}{3} \\x=12$

Therefore, the smaller number equates to 12.

3) Use substitution to solve for the greater number

$x+y=43$

Plug in x as 12

$12+y=43$

Subtract both sides by 12 to isolate y

$12+y-12=43-12\\y=31$

Therefore, the greater number equates to 31.

I hope this helps!

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3 years ago