Quantity of gasoline needed by a car to run 800 miles = 30 gallons
Quantity of gasoline needed by a car to run 1 mile =
= 30 ÷ 800
= 0.0375 gallons
So , to run 1 mile a car would need = 0.0375 gallons of oil
To run 700 miles the quantity of gasoline needed =
= 700 × 0.0375
= 26.25 gallons of gasoline
Therefore , a car will use 26.25 gallons of gasoline on a trip of 700 miles .
Answer:
36 minutes
Step-by-step explanation:
helicopter 1 is ahead of helicopter 2 by 90 miles
the difference in their speeds is 150 mph
90/150=3/5 of hour
3/5*60=36 minutes
The derivative of 1/logx is With the chain rule.
1log(x)=log(x)−1 is ,= -1xlog(x)2 .
The by-product of logₐ x (log x with base a) is 1/(x ln a). Here, the thrilling issue is that we have "ln" withinside the by-product of "log x". Note that "ln" is referred to as the logarithm (or) it's miles a logarithm with base "e".
The by-product of 1/log x is -1/x(log x)^2. Note that 1/logx is the reciprocal of log.

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Answer:
, The driver is 350 feet below sea level.
Step-by-step explanation:
The distance of the driver from the sea level is given by the following expression:




The driver is 350 feet below sea level.