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3 years ago

If y is directly proportional to x and y = 11 when x = 6 , what is the value of y when x = 9

1 answer:

3 0

Since we are given that y is directly proportional to x and that when y = 11, x equals 6, we can set up a proportion. Before doing that however, we need to note that the question is asking for the value of y when x = 9. Here is the equation:
$\frac{11}{6} = \frac{y}{9}$
Now, just cross multiply and solve for y to get a value of 16.5. Therefore, the value of y when x = 9 is 16.5. Hope this helped and have a phenomenal day!

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Equivalent ratios to 16:12 and 12:16

gtnhenbr [62]

It is 36:24 and 24:36

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3 years ago

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(x-1)(x-3)(x+5)(x+7)=297

mihalych1998 [28]

First simplify the expression into polynomial form,

$(x-1)(x-3)(x+5)(x+7)=297$

$x^4+8x^3-10x^2-104x+105=297$

$x^4+8x^3-10x^2-104x-192=0$

Now factor into,

$(x-4)(x+8)(x^2+4x+6)=0$

Which means the solutions are,

$x-4=0\implies\boxed{x_1=4}$

$x+8=0\implies\boxed{x_2=-8}$

and then two complex solutions because determinant of the third factor $D\lt0$ ,

$x^2+4x+6=0$

$x^2+4x+4=-2$

$(x+2)^2=-2\implies\boxed{x_3=i\sqrt{2}-2},\boxed{x_4=-i\sqrt{2}-2}$

Hope this helps :)

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3 years ago

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Find a number that satifies the inequality x<-3

olga2289 [7]

It could basically be anything smaller than -3. So, some examples are -4,-5-,-6,-7,-8,-9,-10, and so on.

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2 years ago

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If anyone's good with interquartile range, median, upper quartile, lower quartile stuff, please help ASAP!

kramer

Answer: B, Range is 16, IQR is 7

Step-by-step explanation:

Quartiles:

Quartiles mark each 25% of a set of data:

The first quartile Q1 is the 25th percentile

The second quartile Q2 is the 50th percentile

The third quartile Q3 is the 75th percentile

The second quartile Q2 is easy to find. It is the median of any data set and it divides an ordered data set into upper and lower halves. The first quartile Q1 is the median of the lower half not including the value of Q2. The third quartile Q3 is the median of the upper half not including the value of Q2.

How to Calculate Quartiles:

Order your data set from lowest to highest values

Find the median. This is the second quartile Q2.

At Q2 split the ordered data set into two halves.

The lower quartile Q1 is the median of the lower half of the data.

The upper quartile Q3 is the median of the upper half of the data.

If the size of the data set is odd, do not include the median when finding the first and third quartiles. If the size of the data set is even, the median is the average of the middle 2 values in the data set. Add those 2 values, and then divide by 2. The median splits the data set into lower and upper halves and is the value of the second quartile Q2.

How to Find Interquartile Range

The interquartile range IQR is the range in values from the first quartile Q1 to the third quartile Q3. Find the IQR by subtracting Q1 from Q3.

IQR = Q3 - Q1

How to Find the Minimum:

The minimum is the smallest value in a sample data set.

Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the minimum is the smallest value x1. The formula for minimum is:

Min=x1=min(xi)ni=1

How to Find the Maximum:

The maximum is the largest value in a sample data set.

Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the maximum is the largest value xn.

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2 years ago

How can the equations of lines help you identify whether the lines are perpendicular, parallel, or nether?

Natali5045456 [20]

Answer:

We can determine whether two lines are parallel by comparing their slopes. If the slopes are the same and the y-intercepts are different, the lines are parallel. If the slopes are different, the lines are not parallel. Unlike parallel lines, perpendicular lines do intersect. Their intersection forms a right, or 90-degree, angle.

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3 years ago