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Artemon [7]
3 years ago
14

May someone help me with this?

Mathematics
1 answer:
Sindrei [870]3 years ago
5 0
I believe these are the answers:

1: maybe A? i’m not sure on this one
2:-4,2?
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Ryan runs 100 m two times. His times were 14.19 s and 13.78 s. Daniel runs 100 m two times. His times were 15.77 s and 16.24 s.
MakcuM [25]

14.19 + 13.78 = 27.97 seconds for Ryan

15.77 + 16.24 = 32.01 seconds for Daniel

32.01 - 27.97 = 4.04 seconds greater

3 0
4 years ago
Read 2 more answers
(1 point) Consider n=20 independent flips of a fair coin. Say that a changeover occurs whenever an outcome differs from the one
77julia77 [94]

Answer:

9.5

Step-by-step explanation:

There is no changeover in the first throw. The probability of each changeover is 1/2 and it doesnt depend on the other changeovers. The only thing that modifies each experiment is the result of the previous flip, but regardless of weather it was tails or heads, the probability will always be 1/2.

Since the coin is flipped 20 times and the first time there is no changeover, there are a total of 19 experiments. All of them independent and with probability 1/2. Therefore, the total amount of changeovers for 20 flips is a random variable with distribution Binomial B(19,0.5), the expected value of a Binomial B(n,p) is n*p. In this case, the expected value of changeovers for n=20 is 19*0.5 = 9.5.

5 0
3 years ago
To use trigonometric functions to find sides and angles of right triangles. the functions sine, cosine, and tangent are called t
krok68 [10]

I am not sure what the question is but here is how you use trig functions:

sine of the angle = side opposite the angle ÷ hypotenuse

cosine of the angle = side adjacent to the angle ÷ hypotenuse

tangent of the angle = side opposite the angle ÷ side adjacent to the angle

4 0
3 years ago
What is the minimum number of triangles required to construct a 10 sided polygon
kupik [55]

10 Triangles fit inside a Decagon

Hope it helps :)

5 0
4 years ago
suppose a sample of 1305 tenth graders is drawn. Of the students sampled, 1044 read above the eighth grade level. Using the data
Inessa05 [86]

Answer: (0.771,\ 0.829)

Step-by-step explanation:

Given : Significance level : \alpha: 1-0.99=0.01

Critical value : z_{\alpha/2}=2.576

Sample size : n=1305

The proportion of tenth graders read above the eighth grade level. =p=\dfrac{1044}{1305}=0.8

The confidence interval for population proportion is given by :-

p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}\\\\=0.8\pm(2.576)\sqrt{\dfrac{0.8(1-0.8)}{1305}}\\\\\approx0.8\pm0.029\\\\=(0.771,\ 0.829)

Hence, the 99% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.771,0.829) .

4 0
3 years ago
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