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geniusboy [140]
2 years ago
8

Luego de su cumpleaños, Benjamín ha decidido donar la tercera parte del dinero que recibió de regalo de sus familiares a una fun

dación. Considerando las variables cantidad de dinero recibido por Benjamín y cantidad de dinero que donará Benjamín. a. ¿Cuál es la variable dependiente en esta situación.
Mathematics
1 answer:
Aloiza [94]2 years ago
3 0

Answer:

The dependent variable is the amount of money he received for birthday.

Step-by-step explanation:

After his birthday, Benjamin has decided to donate a third of the money he received as a gift from his relatives to a foundation. Considering the variables amount of money received by Benjamin and amount of money that Benjamin will donate. to. What is the dependent variable in this situation.

Here, the money he received for the birthday is x.

So, he donated x/3.

The variable is the money which he gets, so the dependent variable is amount of money he received for the birthday.

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2 years ago
Please help with this I am very stuck because I am horrible at math
tigry1 [53]

Answer:

20

Step-by-step explanation:

6 0
3 years ago
Is (0,5) a solution to the equation y=2x?​
klio [65]

Answer:

No.

Step-by-step explanation:

If (0,5) is a solution to y=2x, then 5=2(0) has to be true.

It is not because 5=2(0) is not true.

2(0)=0 and 0 is definitely not 5.

An example of a point on y=2x is (5,10) since 10=2(5) is true.

3 0
3 years ago
Read 2 more answers
What is the answer to (x-4)-(-6+x) ?
Likurg_2 [28]
X - 4 +6 -x
x - x = -2

0 = -2

No solution
5 0
2 years ago
Read 2 more answers
The 12th term of a sequence is 41 and the 15th term is 140. What is the nth term?
OLga [1]
An= mth term.
an=a₁+(n-1)*d

a₁₂=41
a₁₅=140

a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d 
a₁+11d=41    (1)

a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d 
a₁+14d=140    (2)

With the equiations (1) and (2)  build a system of equations
a₁+11d=41
a₁+14d=140

we solve it.
-(a₁+11d=41)
  a₁+14d=140
--------------------
       3d=99  ⇒d=99/3=33

a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322

an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n

an=-355+33n

To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
3 0
3 years ago
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