Step 1. Simplify brackets

Step 2. Simplify
13
Done! :)
Your answer is A. 13 Hope this helps!
Conservation of Energy:
As a projectile is launched into the air KE is at its maximum. As the projectile gains altitude PE becomes greater than KE. At the top of its arc, PE is at its maximum. The whole cycle reverses itself on the way down.
An apple is not an organism, but the cells within it are
The suppression of glycolysis is responsible for a large portion of the control of gluconeogenesis.
Discussion about the statement:
The cytosol is the site of all glycolysis and gluconeogenesis processes. The rate at which glucose is produced in the body is inversely related to the intake of carbohydrates. The suppression of glycolysis is responsible for a large portion of the control of gluconeogenesis.
Fructose 2,6-bisphosphate is an intermediate that plays a crucial role in controlling both glycolysis and gluconeogenesis. This metabolite's presence can promote glycolysis and prevent gluconeogenesis.
Control of Gluconeogenesis and Glycolysis
- At various crucial stages of glycolysis and gluconeogenesis, metabolic control takes place. The catalysts that accelerate each of these stages can be activated or inhibited by outside forces, for example, the quantity of a molecule that comes after. The conversion of glucose and ATP into glucose 6-phosphate is the first controlled step in glycolysis. Keep in mind that hexokinase catalyzes this process.
- High levels of blood glucose, AMP, and low levels of cellular ATP all trigger the activation of hexokinase. In other words, the glycolysis process is enhanced when blood glucose levels are high. Whenever cellular ATP levels are low and AMP levels are high, glycolysis is also increased. Both of these instances show that the cell is short on energy and may be directly influenced to create additional energy.
Learn more about glycolysis here:
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Answer:
16.66 %
Explanation:
The receptors that are bound with the ligand can be calculated by the formula as follows:
Kd = [R] [L]/[RL]
Here, Kd is dissociation constant = 1.5 mM
R is free receptor concentration = 10 mM
L is free ligand concentration = 2.5 mM
The values needs to be constitute to find the percentage of receptors that are bound to ligand.
Put all the values
1.5 = 10 × 2.5 / RL or RL = 25 /1.5
So RL = 16.66
Hence 16.66 % of receptor is bound to substrate.
Thus, the answer is 16.66%