Yes. The answer is 135.07 and rounded to the nearest tenth is 135.1 cm.
Check the picture below.
so to find the surface area of the triangular prism, we simply add the areas of each of the figures composing it, as you can see is really just 2 triangles an 3 rectangles.
![\bf \stackrel{\textit{\Large Areas}}{\stackrel{triangles}{2\left[ \cfrac{1}{2}(4)(3) \right]}+\stackrel{\textit{rectangles}}{(3\cdot 10)+(4\cdot 10)+(5\cdot 10)}}\implies 12+30+40+50\implies 132](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7B%5CLarge%20Areas%7D%7D%7B%5Cstackrel%7Btriangles%7D%7B2%5Cleft%5B%20%5Ccfrac%7B1%7D%7B2%7D%284%29%283%29%20%5Cright%5D%7D%2B%5Cstackrel%7B%5Ctextit%7Brectangles%7D%7D%7B%283%5Ccdot%2010%29%2B%284%5Ccdot%2010%29%2B%285%5Ccdot%2010%29%7D%7D%5Cimplies%2012%2B30%2B40%2B50%5Cimplies%20132)
now, to get the volume is simply the area of the triangular face times the length, well, we know the area of one of the triangles is 6, times 10 is just 6*10 = 60.
Answer:
Maybe. Either 2/4 or 1/4.
Step-by-step explanation:
If you flip a coin 100 times, ABOUT 50 percent will be heads up. Therefore it's not unlikely it up land heads up 2 out of 4 times, but its not unlikely it will be heads down either.