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Sophie [7]
2 years ago
11

You've flipped the coin 3 times, and it has come up heads once. The cumulative fraction of heads is currently 1/3. If you flip t

he coin once more time, will it land heads up to make the cumulative fraction 2/4?
Mathematics
1 answer:
Contact [7]2 years ago
7 0

Answer:

Maybe. Either 2/4 or 1/4.

Step-by-step explanation:

If you flip a coin 100 times, ABOUT 50 percent will be heads up. Therefore it's not unlikely it up land heads up 2 out of 4 times, but its not unlikely it will be heads down either.

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vitfil [10]
<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

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3 years ago
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ddd [48]
Distribute ^4 to both 2 and q^5

2^4 = 2 x 2 x 2 x 2 = 16
(q^5)^4 = q^20

16(q^20) = 16q^20 

16q^20 is your answer

hope this helps
3 0
3 years ago
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