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QveST [7]
2 years ago
5

A bottle of milk is 63% full and contains 1260ml of milk.

Mathematics
1 answer:
vazorg [7]2 years ago
4 0

9514 1404 393

Answer:

  2 liters

Step-by-step explanation:

The applicable proportion can be written ...

   amount/percentage = 1260 mL/63% = x/100%

  2000 mL = x = 2 liters

The full carton held 2 liters of milk.

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Please help me, I need answers in 2 days. Please give answers in one picture otherwise i cannot view it without paying. Would be
solniwko [45]

Answer:

Step-by-step explanation:

i hope this is good enough

6 0
3 years ago
Brody worked 8.5 hours at Food Lion this week and made $78.20. Based on the number of hours Brody worked and how much he was pai
Lynna [10]

Answer:

1 hour = $9.2

Step-by-step explanation:

The question says that:

Brody makes $78.20 in 8.5 hours.

So,

8.5 hours = $78.20

We need to find 1 hour pay.

So, divide both sides of the above equation by 8.5

8.5 / 8.5 hours = $78.20 / 8.5

1 hour = $9.2

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
6 0
3 years ago
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
Can someone help me please?? in Algblra2 - Variations, Progression, and Theorems
VashaNatasha [74]
If (y-1) is a factor of f(y), f(y)=0 when y=1.  So if you find that f(1)=0, then (y-1) is a factor of f(y).

f(y)=y^3-9y^2+10y+5

f(1)=1-9+10+5=7

Since f(1)=7, (y-1) is not a factor.
5 0
4 years ago
Please help me with questions 6
loris [4]
Since A = bh
and A = 198 and b = 18?
h = A/b
= 198/18
= 11
6 0
3 years ago
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