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Sophie [7]
2 years ago
12

Tyler looks at a map on his phone. He zooms in until the map scale for centimeters to kilometers is 0.3 to 1/5. How many centime

ters does the map use to show 1 kilometer?
Mathematics
1 answer:
lutik1710 [3]2 years ago
5 0

one kilometer is equal to a hundred thousand centimeters

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¿cuanto pesa cada uno de nuestros 3 personajes?
sergij07 [2.7K]

Resolviendo el sistema de ecuaciones veremos que:

  • niña = 23kg
  • niño = 28kg
  • perro = 18kg.

<h3>¿Como resolver el sistema de ecuaciones?</h3>

Aqui tenemos el sistema de ecuaciones:

Niña + niño = 51kg

Niño + perro = 46 kg

Niña + perro = 41kg

Para resolver esto, lo primero que debemos hacer es aislar una variable en una de las ecuaciones, por ejemplo, podriamos aislar "perro" en la tercera:

perro = 41kg - niña

Ahora reemplazamos eso en la segunda para obtener:

niño + (41kg - niña) = 46kg

niño - niña = 46kg - 41kg = 5kg

niño = niña + 5kg

Ahora logramos obtener la variable "niño" en terminos de la variable "niña". Podemos reemplazar esto en la primera ecuacion del sistema.

niña + niño = 51kg

niña + (niña + 5kg) = 51kg

2*niña = 51kg - 5kg = 46kg

niña = 46kg/2 = 23kg.

Ahora que sabemos esto, usamos las otras ecuaciones para encontrar el peso del niño y el perro:

niño = niña + 5kg = 23kg + 5kg = 28kg

perro = 41kg - niña = 41kg - 23kg = 18kg.

Sí quieres aprender más sobre sistemas de ecuaciones, puedes leer:

brainly.com/question/17174746

6 0
2 years ago
if trapezium of area 140 cm horsepower sides 10 cm apart and one of them decides is 16 cm longfind the area find the length of t
Vilka [71]

Given :

  • Area of the trapezium is 140 cm².
  • Its height is 10 cm.
  • One of the parallel side is 16 cm.

To Find :

  • The other parallel side.

Solution :

  • Let the other parallel side be x

We know that,

{ \qquad \: \pmb{ \dfrac{1}{2} \times (sum \: of \: the \: parallel \: sides) \times height} = \pmb{Area_{(trapezium)}}}

Now, Substituting the given values in the formula :

\qquad { \dashrightarrow \: { \sf{ \dfrac{1}{2} \times (16 + x)\: \times 10 \: = {140}}}}

\qquad { \dashrightarrow \: { \sf{ 5 \times (16 + x)\  \: = {140}}}}

\qquad { \dashrightarrow \: { \sf{ 80 + 5x = {140}}}}

\qquad { \dashrightarrow \: { \sf{  5x = {140 - 80}}}}

\qquad { \dashrightarrow \: { \sf{  5x = {60}}}}

\qquad { \dashrightarrow \: { \sf{  x = { \dfrac{60}{5} }}}}

\qquad { \dashrightarrow \: { \pmb{  x = { 12 }}}}

Therefore,

  • The other parallel side of the trapezium is 12 cm.
8 0
2 years ago
Please help. solve for x
malfutka [58]

Step-by-step explanation:

Given,

Base of the triangle

2 \sqrt{6}

Hypotenuse of the triangle = 5

Height of the triangle = x

Therefore, According to Pythagoras Theorem,

{base}^{2}  +  {height}^{2}  =  {hypotenuse}^{2}

=  >  {(2 \sqrt{6)} }^{2}  +  {x}^{2}  =  {5}^{2}

=  > 24 +  {x}^{2}  = 25

=  >  {x}^{2}  = 25 - 24

=  >  {x}^{2}  = 1

=  > x =  \sqrt{1}

=  > x = 1

Hence, the required value of <u>x is 1.</u>

7 0
2 years ago
What is 4 plus 8 and 3
jarptica [38.1K]
4+8+3 would be 15 because 4 plus 8 is 12 and 12 plus 3 is 15

Hope this helps
7 0
3 years ago
Read 2 more answers
Julie started solving the equation 3x=4+2(3-x)
BARSIC [14]

Answer:

x=2

Step-by-step explanation:

3x=4+2(3-x)

Distribute 2 to 3 and x

3x=4+6-2x

Add 2 to both side of the equal sign and combine 4 and 6

5x=10

divide both sides by 5

x=2

5 0
3 years ago
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