Question

The number of radioactive nuclides from a radioactive source has reduced to 1/6

Answer 1

Answer:

λ = 0.03 s⁻¹

Explanation:

The formula for decay constant can be used as follows:

$N = N_oe^{-\lambda t}\\\\\frac{N}{N_o} = e^{-\lambda t}$

where,

$\frac{N}{N_o}$ = ratio of remaining nuclei to the initial value of nuclei = $\frac{1}{6}$ = 0.167

t = time = 60 s

λ = decay constant = ?

Therefore,

$0.167 = e^{-\lambda(60\ s)}\\\\-\lambda (60\ s) = ln(0.167)\\\\\lambda = \frac{-1.7917}{- 60\ s}$

λ = 0.03 s⁻¹