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kvasek [131]
2 years ago
9

Two boys with masses of 40 kg and 60 kg stand on a horizontal frictionless surface holding the ends of a light 10-m long rod. Th

e boys pull themselves together along the rod. When they meet the 40-kg boy will have moved what distance?.
Physics
1 answer:
kari74 [83]2 years ago
7 0

When they meet the 40-kg boy will have moved a distance of 6 m.

Displacement of the 40 kg boy

The displacement of the 40 kg boy is calculated from the principle of center mass.

X(40 kg) = (60 x 10 m    +  40 x 0)/(40 kg + 60 kg)

X(40 kg) = (600)/(100) = 6 m

X(60 kg) = (60 x 0    +  40 x 10 m)/(40 kg + 60 kg)

X(60 kg) = (400)/(100) = 4 m

Thus, when they meet the 40-kg boy will have moved a distance of 6 m.

Learn more about center mass here: brainly.com/question/13499822

#SPJ1

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Answer:

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Strain is the ratio between the change in length/area/volume to the original length/area/volume of the material (and hence a dimensionless quantity). Basically, it gives us a measure of the change in dimensions due to the stress experienced.

So, for the given problem,

Y=\frac{Stress}{\Delta L/L}

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The temperature of one substance is 90 degrees F and another
valina [46]

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A woman drives a car from one city to another with different constant speeds along the trip. She drives at a speed of 80.0 km/h
romanna [79]

Answer:

Total distance traveled= 75.36km (point at which she reaches her destination.)

Explanation:

With the speed and time data we can calculate the distance traveled on each path, but first we must transform the time units from minutes to hours:

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distancie= v*t = 80km/h * 0.42h =33.6km

Second ride:

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Stop: 60min= 1h  distance=0km

third ride:

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Answer:

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