A right triangle. Hope this helps.
Answer:
See below
Step-by-step explanation:
Remember that quadratic functions are parabolas when graphed. The solutions are where the parabola crosses the x-axis.
1. The vertex of the parabola in f(x) is (0, 9) which is above the x-axis and the parabola opens up. So the parabola does not cross the x-axis. Therefore the solutions are imaginary.
2. The vertex of the parabola in g(x) is (9, 0) which is on the x-axis and parabola opens up. Therefore, there is a double solution.
3. The vertex of the parabola in h(x) is (-1, -9) which is below the x-axis and the parabola opens up. Therefore, there are two real solutions.
I know this is a long explanation, but that is a way of looking at the problem.
Answer: Here's what I got:
Step-by-step explanation:
Is this what you wanted? My answer is A=22in²
Here's how I got it:
A=2(wl+hl+hw)=2·(1·3+2·3+2·1)=22in²
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Answer:
6562331215
Step-by-step explanation:
Answer:
2x3x5=120
Step-by-step explanation:
