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Marina86 [1]
2 years ago
9

In triangle JKL, JKL is a right angle, KM and is an altitude. JL=20 and ML=15, find KL

Mathematics
2 answers:
alexandr1967 [171]2 years ago
7 0


KL= 17.32 because KML is a right triangle

ss7ja [257]2 years ago
4 0

Answer:

KL = 17.32

Step-by-step explanation:

KL² = (M L)(J L)

KL² = (15)(20)

KL²=300

√KL²= √300

KL = 17.32

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Start off by distributing the numbers into the parentheses:

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-15x - 10 - x + 3 = -16x - 20 + 13
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(When you get 0=0 when solving for a variable, that means that said variable will have infinite solutions, that is, any number plugged into the equation will work)
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Step-by-step explanation:

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Pedro grew 4 1/3 inches during a 3 ½ month growth spurt. If his growth spurt continued at the same rate how much did he grow in
borishaifa [10]

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Please help me it’s a formative grade
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Based on the information given say whether or not △ABC∼△FED. Explain your reasoning.
GalinKa [24]

Answer:

Yes, △ABC ∼ △FED by AA postulate.

Step-by-step explanation:

Given:

Two triangles ABC and FED.

m∠A = m∠B

m∠C = m∠A + 30°

m∠E = m∠F = x

m∠D = 2x-20°.

Now, let m∠A = m∠B = y

So, m∠C = m∠A + 30° = y+30

Now, sum of all interior angles of a triangle is 180°. Therefore,

m∠A + m∠B +  m∠C = 180

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Therefore, m∠A = 50°, m∠B = 50° and m∠C =  m∠A + 30° = 50 + 30 = 80°.

Now, consider triangle FED,

m∠D+ m∠E + m∠F = 180

2x-20+x+x=180\\4x=180+20\\4x=200\\x=\frac{200}{4}=50

Therefore,  m∠F = 50°  

m∠E = 50° and  

m∠D =  2x-20=2(50)-20=100-20=80\°

So, both the triangles have congruent corresponding angle measures.

m∠A = m∠F = 50°

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m∠C = m∠D = 80°

Therefore, the two triangles are similar by AA postulate.

5 0
3 years ago
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