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vodka [1.7K]
3 years ago
12

Determine the x and y-intercept for -3x + 2y = 12 PLEASEEEE HELPP THANK U ​

Mathematics
1 answer:
scZoUnD [109]3 years ago
7 0

To find the x-intercept, let y = 0.

You get 4x-0=12

x = 3

x-intercept is (3,0)

----------------------------

To find the y-intercept, let x = 0.

You get 0-2y=12

y = -6

y-intercept is (0,-6)

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Tim is running a distance of 30 city blocks. Each block is the same length. It took him 6 minutes to run 10 blocks. At the same
mestny [16]

10 blocks = 6 min

30 blocks = 18 min

You can answer this because you know that 10 x 3 is 30, so if if the number of blocks tripled then the amount of time should triple as well because he's running at the same rate.

8 0
3 years ago
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Mr. Rivera can grade 18 math teat in 15minutes. What is the teachers unit rate?
Andru [333]

In this question, you're trying to find the unit rate in which the teacher can grade tests.

A unit rate is another word for "rate of change".

This means that we have to find how many tests the teacher could grade in 1 minute.

To find the unit rate, divide 18 by 15

18 ÷ 15 = 1.2

This means that Mr. Rivera can grade 1.2 tests in 1 minute.

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1.2 tests

6 0
3 years ago
A factory has three machines making energy drinks. When all three machines are running, 520 drinks are made each hour. When only
Vinil7 [7]

Let A, B and C be the amount machines A, B and C, respectively, produce each hour alone.

With all three machines together produce 520 drinks each hour, we know that the addition of the amount that each produces each hour is equal to 520, that is.

A+B+C=520_{}

Now, similarly, machines A and B produce together 320 drinks each hour, so the sum of the amounts A and B produce each hour is equal to 320, so:

A+B=320

If machine C produce 30 more drinks than B each hour, than the amount of B plus 30 will be the amount of C:

C=B+30

So, we got the system of equations:

\begin{gathered} A+B+C=520 \\ A+B=320 \\ C=B+30 \end{gathered}

To solve, notice that A + B is known, because of the second equation, so we can substitute A + B by 320 in the first equation:

\begin{gathered} (A+B)+C=520 \\ 320+C=520 \\ C=520-320=200 \end{gathered}

Now, we can substitute C into the third equation and solve for B:

\begin{gathered} C=B+30 \\ 200=B+30 \\ B+30=200 \\ B=200-30=170 \end{gathered}

And, finally, we can substitute B into the second equation and solve for A:

\begin{gathered} A+B=320 \\ A+170=320 \\ A=320-170=150 \end{gathered}

Answers:

First box:

A+B+C=520

Second box:

A+B=320

Third box:

C=B+30

Fourth box:

150

3 0
1 year ago
I need the hour and the minuts too thank you
hammer [34]

Answer:

5hrs & 30mins

Step-by-step explanation:

7 0
3 years ago
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A)y=3x<br> b)2x+2<br> Answer choices
tino4ka555 [31]

y=2x+2 is the correct answer.

Hope it helps...

Regards,

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