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Margaret [11]
3 years ago
13

Fvgbhjnbvcxdfghj (ignore this)

Mathematics
1 answer:
adelina 88 [10]3 years ago
3 0
I should be on the black dot ☺️

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The distance to a thunderstorm is the number of seconds between seeing the lightning and hearing
ZanzabumX [31]

Answer:

distance or time?????????

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4 years ago
Match each set of numbers with their least common multiple
myrzilka [38]

27, 12, and 36  = 108

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Factor the following linear expressions using the greatest common factor: If it can not be factored, please write 'can not be fa
adell [148]

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1. factor

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Estimate 38¼ - 14¾ by rounding each number to the nearest whole number.
Gemiola [76]

By rounding each number to the nearest whole number is  23.5

Given,

Estimate 38¼ - 14¾

and, by rounding each number to the nearest whole number.

Now, The solution is :

=38¼ - 14¾ = 153/4 - 59/4

=> \frac{153-59}{4}

=> 94/4

=> 23.5

Estimation a number to the nearest whole number:

To round a number to the nearest whole number, you have to look at the first digit after the decimal point. If the digit is less than 5 (1, 2 , 3, 4) we don't have to do anything, but if the digit is 5 or greater (5,6,7,8,9) we must round up.

Hence, By rounding each number to the nearest whole number is  23.5

Learn more about Whole Numbers at:

brainly.com/question/14783707

#SPJ1

6 0
1 year ago
An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th
butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that \pi = 0.2

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}

0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}

\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}

(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}

n = 5615

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now \pi = 0.12, n = 5615.

We have to find M.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 2.81\sqrt{\frac{0.12*0.88}{5615}}

M = 0.012

7 0
3 years ago
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