The length of the radius will be 22 units.
<h3>What is the radius?</h3>
The radius of a circle is defined as the distance of the center of the circle to its outer layer. It is a locus of a point present at some distance from the center point.
Now from the question, we have an expression:
By solving the above equation we get
Hence the length of the radius will be 22 units.
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3x - 2y = 18
Wherever the line crosses the
x-axis, y=0. 3x = 18
x = 6
The x-intercept is (6, 0) .
3x - 2y = 18
Wherever the line crosses the
y-axis, x=0. - 2y = 18
y = -9
The y-intercept is (0, -9) .
Answer:
The equation of the line that passes through the points
(1,-6) and (-4,9)
is
y=-3x-3
So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
Let's call the two numbers a and b. So we know that the difference of the two numbers is 36:
a - b = 36
And we know that their sum is 286:
a + b = 286
We can use either of these equations to solve for one of the variables in terms of the other variable. Let's use the first and solve for a:
a - b = 36
a = 36 + b
Now we plug this into the other equation and solve for b there:
(36 + b) + b = 286
36 + 2b = 286
2b = 250
b = 125
