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solniwko [45]
3 years ago
14

Please me ASAP......and follow me too​

Mathematics
2 answers:
Kay [80]3 years ago
8 0

Answer:

I like agree like with like the other like person

trasher [3.6K]3 years ago
4 0

Answer:

Assuming this is a x

(x^3y^3,xy^3)

I hope this is good enough:

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Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.75241,0.06281)  

Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 -2*0.06281 =5.6121

And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 +2*0.06281 =5.8886

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

5 0
3 years ago
6r-r+8(15-r)+23-6 solve
lys-0071 [83]
Your answer is -3r + 137

thats the answer i think
4 0
3 years ago
Read 2 more answers
Which of the following is the maximum value of the equation y=-2x^2-3x+4
mylen [45]
Y=-2x^2-3x+4

dy/dx=-4x-3, d2y/dx2=-4

When the velocity, dy/dx=0, then y(x) is at an absolute maximum because the acceleration is a constant negative, -4.

dy/dx=0 only when -4x-3=0, -4x=3, x=-3/4

y(-3/4)=5.125

So the maximum value of y is 5 1/8
4 0
4 years ago
What is the solution to 2 log Subscript 9 Baseline (x) = log Subscript 9 Baseline 8 + log Subscript 9 Baseline (x minus 2) x = n
Kaylis [27]

Answer:

\large\boxed{\large\boxed{x=4}}

Step-by-step explanation:

The equation to solve is:

            2\log_9 x=\log_9 8+\log_9 (x-2)

1. <u>On the left-hand side </u>use: "The product of a constant by a logarithm is equal to the logarithm raised to the constant"

Thus, the left-hand side is:

               2\log_9 x=\log_9 x^2

2. On the <u>right-hand side</u> use "The sum of two logarithms with the same base is the logarithm of the product":

Then, on the right-hand side:

        \log_9 8+\log_9 (x-2)=\log_9 8(x-2)

3. <u>Make them equal</u>:

      \log_9 x^2=\log_9 8(x-2)

4. Since the two functions are the same, <u>make the arguments equal</u>:

     x^2=8(x-2)

5. <u>Solve the equation</u>:

        x^2=8x-16\\\\x^2-8x+16=0\\\\(x-4)^2=0\\\\x-4=0\\\\x=4\leftarrow solution

4 0
3 years ago
Read 2 more answers
1/3x +5.....x= -6 it is equal to what?
garri49 [273]

3 is the answer you are looking for


6 0
4 years ago
Read 2 more answers
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