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Darina [25.2K]
3 years ago
13

6r-r+8(15-r)+23-6 solve

Mathematics
2 answers:
Komok [63]3 years ago
7 0
Your answer is -3r + 137

Hope this helps!!
lys-0071 [83]3 years ago
4 0
Your answer is -3r + 137

thats the answer i think
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Which of the following is the result of
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Answer:

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3 years ago
K=1/2 mv squared, determined m when v=30 and k=4500.
WITCHER [35]

Given the expression:

\text{ k = }\frac{1}{2}mv^2

At v = 30 and k = 4,500 , let's determine m.

\text{ k = }\frac{1}{2}mv^2\frac{2k}{v^2}\text{ = m }\rightarrow\text{ m = }\frac{2k}{v^2}

We get,

\text{ m = }\frac{2k}{v^2}\text{ = }\frac{2(4,500)}{(30)^2}\text{ = }\frac{9,000}{900}\text{ m = 10}

Therefore, m = 10.

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2 years ago
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4 years ago
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aleksandrvk [35]
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1 year ago
2 fair dice are rolled. what is the probability that the sum is even given that the first die is rolled is a 2?
Llana [10]
<h3>The answer as a fraction is 1/2</h3><h3>In decimal form the answer converts to 0.5 which is equivalent to 50%</h3>

===================================================

Explanation:

"given that the first die rolled is a 2" means we know 100% that the first die shows a 2. Either we can see the die or a friend is telling us the status. Since we know the first die is a 2, this means we can effectively ignore it. Everything will hinge on the second die. If the second die shows an odd number, something like 1, then 2+1 = 3 is the result which is also odd.

The general rule is odd+even = odd and even+even = even.

Therefore, the two dice must together be even for the sum to be even.

Of the six possible ways to roll a die {1,2,3,4,5,6}, there are 3 even values {2,4,6} so the chances of rolling an even number on the second die is 3/6 = 1/2. Again we dont need to consider the first die at all since everything practically hinges on this second die.

8 0
3 years ago
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