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3 years ago

Henry drove 567 miles in 9 hours. At the same rate, how long would it take him to drive 315 miles?

Mathematics

2 answers:

Andrei [34K]3 years ago

8 0

Answer:

in one hour = 567÷9

= 63

hence, to drive 315 miles he would need = 315×63 hours

divide yourself my dear friend.

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WARRIOR [948]3 years ago

4 0

Answer:

5 hours.

Step-by-step explanation:

567/9 = 63mph

315/63 = 5

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$if \: log(x ) = 3 \\ log_{10}(x) = 3 \\ {10}^{3} = x \\ therfore \to \: \boxed{x = {10}^{3} } \\ \\ if \: log(y ) = 2 \\ log_{10}(y) = 2 \\ {10}^{2} = y \\ therfore \to \: \boxed{y= {10}^{2} }$

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$x^2 -7xy =3000y \: then \to \\ x^2 =3000y + 7xy \\ {(10 ^{3} )}^{2} = 3000(10)^{2} + 7( {10}^{3} \times {10}^{2}) \\ {10}^{6} = 3000(10)^{2} + 7( {10}^{3} \times {10}^{2}) \\ {10}^{6} = 3000(10)^{2} + 7( {10}^{5} ) \\ {10}^{6} = 300000 + 700000 \\ \boxed{{10}^{6} = 1000000} \\ hence \: the \: equation \to \: x^2 -7xy =3000y \\ \boxed{ is \: corret}$

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