Answer:
B. f(x) = -x^3 - x^2 + 7x - 4
Step-by-step explanation:
For this problem, we want to find the fastest-growing term in our given expressions and equate them when x is - infinite and when x is infinite to see the given trends.
For each of these equations, we will simply take the terms with the highest power and consider those. The two cases we need to consider is + infinite for x and - infinite for x. Let's check each of these equations.
Note, any value raised to an even power will be positive. Any negative value raised to an odd power will be negative.
<u>[A] - x^4</u>
<em>When x is +∞ --> - (∞)^4 --> f(x) is -∞</em>
<em>When x is -∞ --> - (-∞)^4 --> f(x) is -∞</em>
<em />
<u>[B] - x^3</u>
<em>When x is +∞ --> - (∞)^3 --> f(x) is -∞</em>
<em>When x is -∞ --> - (-∞)^3 --> f(x) is ∞</em>
<em />
<u>[C] 2x^5</u>
<em>When x is +∞ --> 2(∞)^5 --> f(x) is ∞</em>
<em>When x is -∞ --> 2(-∞)^5 --> f(x) is -∞</em>
<em />
<u>[D] x^4</u>
<em>When x is +∞ --> (∞)^4 --> f(x) is ∞</em>
<em>When x is -∞ --> (-∞)^4 --> f(x) is ∞</em>
<em />
Notice how only option B, when looking at asymptotic (fastest-growing) values, satisfies the originally given conditions for the relation of x to f(x).
Cheers.
Answer:
No one knows. Jk just go look at the other brainly links. the question has already been asked and answered so you can go see them there.
Step-by-step explanation:
:)
Im not so sure but, 3x2=6; 2x3=6; 6+6=12
Answer:
its 16m+2
Step-by-step explanation:
you add m and 15 m because they have the same variable.
then you put the two right next to it
Answer:
Brandon
Step-by-step explanation:
GIVEN: Branden and Pete each play running back. Branden carries the ball 
times for 
yards, and Pete has 
carries for 
yards.
TO FIND: Who runs farther per carry.
SOLUTION:
Total yards traveled by Brandon 
No. of times ball carried by Brandon 
Average yards per carry for Brandon 
Total yards traveled by Pete 
No. of times ball carried by Pete 
Average yards per carry for Pete
≅ 
As the number of yards per carry is higher for Brandon , therefore he runs farther per carry.
