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olya-2409 [2.1K]
2 years ago
5

Find the sum of the first 50 terms -6, -2, 2, 6,…

Mathematics
1 answer:
Roman55 [17]2 years ago
3 0

Answer:

4600

Step-by-step explanation:

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Solve each quadratic equation by factoring and using the zero product property.
Iteru [2.4K]

Answer:

x=5                            x=6

Step-by-step explanation:

x^2 - 8x + 30 = 3x

Subtract 3x from each side

x^2 - 8x-3x + 30 = 3x-3x

x^2 - 11x + 30 = 0

What 2 numbers multiply to 30 and add to -11

-5*-6 = 30

-5+-6 = -11

(x-5) (x-6) =0

Using the zero product property

x-5 = 0  and x-6 =0

x-5+5 =0+5   and x-6+6 =0+6

x=5                            x=6

7 0
3 years ago
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I need help on this. I will give you the brainliest
Ludmilka [50]

Answer:

4x-3y= 36-12=24 make me the brainlest

7 0
3 years ago
Pls help and no unnecessary typin* I will report
satela [25.4K]

\large\bf{\underline{Given :}}

  • An isosceles triangle ABC
  • AD is a bisector of ∠‎A

__________________________________________

\large\bf{\underline{To \:prove :}}

  • BD = DC

__________________________________________

\large\bf{\underline{In \: triangle \: ABD\:and\: triangle\:ADC}}

{⟹AD = AD\:\:\:\:\:\:\:\:\:\:\:\:\:\:( common)}

{⟹∠BAD = ∠CAD\:\:\:\:\:\:\:\:\:( given : AD \:is \:bisector \:of \:∠A )}

{⟹∠ABD = ∠ACD\:\:\:\:\:\:\:\:\:( given : angles\: in \:isosceles\: trianlge )}

\large\bf{\underline{Hence}}

  • By ASA criteria ∆ABD congurant to ∆ADC

__________________________________________

\large\bf{\underline{So}}

  • By CPCT ( corresponding parts of congurant triangle )

\large\bf{BD = DC}

__________________________________________

\large\bf{\underline{Note :}}Slide to view full answer.

6 0
2 years ago
Given that cos θ = –12∕13 and θ is in quadrant III, find csc θ.
Trava [24]

Answer:

A

Step-by-step explanation:

We are given:

\displaystyle \cos(\theta)=-\frac{12}{13},\,\theta\in\text{QIII}

Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):

o=\sqrt{13^2-12^2}=\sqrt{25}=5

So, the opposite side is 5, the adjacent side is 12, and the hypotenuse is 13.

And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.

Cosecant is given by the hypotenuse over the opposite side. Thus:

\displaystyle \csc(\theta)=\frac{13}{5}

Since θ is in QIII, cosecant must be negative:

\displaystyle \csc(\theta)=-\frac{13}{5}

Our answer is A.

7 0
2 years ago
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20POINTS<br> x-4y=1 and 2 x-8y=2
Rom4ik [11]
First you would take one and move it over to the left side and never leave for why and then you divide by one which would leave for why and it would also have X equals 4Y and then you divide ask my Y and I will just leave you which is XY equals four
4 0
3 years ago
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