Given that X <span>be the number of subjects who test positive for the disease out of the 30 healthy subjects used for the test.
The probability of success, i.e. the probability that a healthy subject tests positive is given as 2% = 0.02
Part A:
</span><span>The probability that all 30 subjects will appropriately test as not being infected, that is the probability that none of the healthy subjects will test positive is given by:
</span>

<span>
Part B:
The mean of a binomial distribution is given by
</span>

<span>
The standard deviation is given by:
</span>

<span>
Part C:
This test will not be a trusted test in the field of medicine as it has a standard deviation higher than the mean. The testing method will not be consistent in determining the infection of hepatitis.</span>
I believe you meant the equal signs to be division symbols haha. The next step would be 18/6.
Let the third side = x.
The sum of any two sides must be greater than the third side
14 + 9 > x
23 > x
14 + x > 9
x > -5
9 + x > 14
x > 5
So 5 < x < 23
Answer:
<h2>
(−y−2)(y−3)</h2>
Step-by-step explanation:
I'm just going to factor it for you.
Factor −y^2+y+6
−y^2+y+6
=(−y−2)(y−3)
Answer:
(−y−2)(y−3)
Answer:
7 and 8 im pretty sure...
Step-by-step explanation:
sorry if its wrong..