Answer:
Probability that the son will be:
color-blind = 1/2
blue eyed = 1/8
blue eyed and color-blind = 1/16
Explanation:
Mother : BbXcX
Father : BbXY
Colorblindness is X linked recessive trait hence will be caused when the son has XcY genotype.
XcX X XY :
Xc X
X XcX XX
Y XcY XY
Half of the sons will have normal vision and other half will be colorblind hence, there is 1/2 probability that the son will be colorblind.
Eye color is autosomal trait and blue color will be produced when the child has bb genotype.
Bb X Bb :
B b
B BB Bb
b Bb bb
1/4 of the children will have blue eyes. Since half of the children are expected to be males, 1/4 * 1/2 = 1/8 sons are expected to have blue eyes.
Probability of a son being blue eyed and color blind will be :
1/8 * 1/2 = 1/16
Answer:
A. damaged her peripheral nervous system because the information regarding taste cannot be transmitted back to her brain.
Explanation:
The nervous system is an important system of our body and is directly related to our survival. This system is linked to the coordination of the organism's various activities and is also responsible for allowing the interpretation of the environment around us.
The nervous system is an important system of our body and allows us to have emotions, to remember an important moment in our lives, to interpret smells, tastes and images, to make movements and even to stay alive through the automatic breathing and heartbeat.
Taste, that is, the sense of taste is directly linked to the peripheral nervous system. For this reason, if Stacey has lost her sense of taste, we can conclude that she has damaged her peripheral nervous system because taste information cannot be transmitted back to her brain.
A. The black moths were more fit for survival, so their phenotype frequency increased.
I just did a project over this in biology and kinda hated it lol but there's the answer, have a gr8 day m8
Answer:
Barr bodies are small bodies that are dark staining bodies that show the inactivated X chromosome, these sex chromatin bodies attach to the membrane of the nucleus of interphase cells.
One less of the total number of X-chromosome (n-1) represents the number of Barr bodies.
Then,
The number of Barr bodies with Klinefelter would be:
Klinefelter (47,XXY): (n-1) = (2-1) = 1 Barr body as here two X chromosome present.
Similarly, for
Turner (45,XO): (n-1) = (1-1) = 0 Barr bodies (X chromosome = 1)
Now, as per the question, the bar bodies for karyotypes given
47,XYY: (n-1) = (1-1) = 0 Barr bodies
47,XXX: (n-1) = (3-1) = 2 Barr bodies
48,XXXX: (n-1) = (4-1) = 3 Barr bodies
It’s TAGCGTTAA they are complementary
