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3 years ago

WILL MARK BRAINLIEST AND WORTH 30 POINTS

Mathematics

1 answer:

BabaBlast [244]3 years ago

5 0

Answer:

The growth factor of f(x) is less than the growth factor of g(x).

Explanation:

$\displaystyle g(x) = 3(4)^x \\ \\ f(x) = 4(3)^x$

x | f(x)

_____

0 | 4

1 | 12

2 | 36

You can tell because the g(x) function is multiplying by 4, while the f(x) function is multiplying by 3.

I am joyous to assist you anytime.

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Pam has 90 m of fencing to enclose an area in a petting zoo with two dividers to separate three types of young animals. The thre

andrew-mc [135]

Answer:

The area function is

$A=\frac{135}{2}x-\frac{9}{2}x^2$ .

The domain and range of A is $(0,15m)$ and $(0, 253.125 m^2]$ .

Step-by-step explanation:

The given length of fencing is $90 m$ .

Let the length and width of each pen be $x$ and $y$ respectively as shown in the figure.

As there are 3 pens, so, the total area,

$A= 3 xy \;\cdots (i)$

From the figure the total length of fencing is $6x+4y$ .

Here, for a significant area for the animals, $x>0$ as well as $y>0$ as $x$ and $y$ are the sides of ben.

From the given value:

$6x+4y=90\;\cdots (ii)$

$\Rightarrow y=\frac {45}{2}-\frac{3x}{2}$

Now, from equation (i)

$A=3x\left(\frac {45}{2}-\frac{3x}{2}\right)$

$\Rightarrow A=\frac{135}{2}x-\frac{9}{2}x^2\;\cdots (iii)$

This is the required area function in the terms of variable $x$ .

For the domain of area function, from equation (ii)

$x=15-\frac{2y}{3}$

$\Rightarrow x$ [as y>0]

So, the domain of area function is $(0,15m)$ .

For the range of area function:

As $x \rightarrow 0$ or $y\rightarrow 0$ , then $A\rightarrow 0$ [from equation (i)]

$\Rightarrow A>0$

Now, differentiate the area function with respect to $x$ .

$\frac {dA}{dx}=\frac{135}{2}-9x$

Equate $\frac {dA}{dx}$ to zero to get the extremum point.

$\frac {dA}{dx}=0$

$\Rightarrow \frac{135}{2}-9x=0$

$\Rightarrow x=\frac{15}{2}$

Check this point by double differentiation

$\frac {d^2A}{dx^2}=-9$

As, $\frac {d^2A}{dx^2}$ , so, point $x=\frac{15}{2}$ is corresponding to maxima.

Put this value back to equation (iii) to get the maximum value of area function. We have

$A=\frac{135}{2}\times \frac {15}{2}-\frac{9}{2}\times \left(\frac {15}{2}\right)^2$

$\Rightarrow A=253.125 m^2$

Hence, the range of area function is $(0, 253.125 m^2]$ .

4 0

3 years ago

Suppose you flip 3 quarters, one at a time. What is the probability that you will

Semenov [28]

Answer:

The probability of the combination {H, T and H} is 0.125.

Step-by-step explanation:

The sample space of flipping a quarter is:

S = {H and T}

The probability of both outcomes is same, i.e. P (H) = P (T) = 0.50.

It is provided that three quarters are flipped one at a time.

The outcomes of all the three quarters are independent of each other.

Compute the probability of the combination {H, T and H} as follows:

$P(\text{H},\text{T and H}) = P(\text{H})\times P(\text{T})\times P(\text{H})$

$=0.50\times 0.50\times 0.50\\=0.125$

Thus, the probability of the combination {H, T and H} is 0.125.

7 0

3 years ago

Line segment XY is tangent to circle Z at point U. Circle Z is shown. Line segment U V is a secant. Line segment X Y is a tangen

Yuri [45]

Answer:

138°

Step-by-step explanation:

∠YUV creates arc YV. Circle Z is made up of arc UV (84°) and arc YV. Solve for the measure of arc YV. (A circle equals 360°)

84° + x = 360°

arc YV = 276°

arc YV is formed from a secant and a tangent. Because of this ∠YUV is half of arc YV.

276° ÷ 2 = 138°

∠YUV = 138°

3 0

2 years ago

Read 2 more answers

Find the volume of a cone with a diameter of 5.5 km

vagabundo [1.1K]

Answer:

$volume = \frac{1}{3} \pi {r}^{2} h \\ = \frac{1}{3} \times \frac{22}{7} \times {( \frac{5.5}{2}) }^{2} \times 11.2 \\ = 88.7 \: {km}^{3}$

4 0

2 years ago

A party mix is made by adding nuts that sell for $2.50 per kg to a cereal mixture that sells for $1 per kg. How much of each sho

sesenic [268]

Answer:

The amount of nuts is 16 kg and cereal mixture is 44 kg to obtain 60 kg of a mix that will sell for $1.40 per kg

Step-by-step explanation:

Let

x=nuts at $2.50 per kg

y=cereal at $1 per kg

x+y=60 kg (1)

2.50x+y=1.40(60) (2)

From (1)

x=60-y

Substitute x=60-y into (2)

2.50x+y=1.40(60)

2.50(60-y)+y=84

150-2.5y+y=84

-1.5y=84-150

-1.5y=-66

Divide both sides by -1.5

y=44 kg

Substitute y=44 into (1)

x+y=60

x+44=60

x=60-44

=16

x=16 kg

3 0

3 years ago