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3 years ago

Please help me with this thanks:) fast!!!

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

3 0

Answer:

$2\sqrt{1.86}$ = 0.95 $2\sqrt{0.95}$ = 0.485 --> (hundredth) 0.49

Step-by-step explanation:

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Its really hard !!!!!!!!!!!!!!!

Tomtit [17]

Answer:

B) 65%

Step-by-step explanation:

4 0

3 years ago

Walt and Hank collect quarters from different states. Walt collected q quarters. Hank collected four fewer quarters than Walt. T

SpyIntel [72]

Answer:

Walt has 37 quarters. Hank has 33.

Step-by-step explanation:

Solve the given equation for q:

0.25q + 0.25q - 1.00 = 17.50

Simplify this, obtaining:

0.50q = 18.50

Simplifying this by multiplying both terms of this result by 100:

50 q = 1850

Thus, q = 1850/50 = 37

Walt has 37 quarters. Hank has 33.

Note that 37 + 33 = 70, and that 70($0.25) = $17.50. So our results are correct.

8 0

4 years ago

You look at a button under a magnifying glass the image of the button is 5 times larger than the buttons actual size and has a d

mash [69]

The diameter of under the magnifying glasses is 6cm, so the actual size is 6÷5cm, the diameter is 1.2 cm

8 0

4 years ago

Find the equation for the linear function based upon this table. y = mx + b

Rudik [331]

Answer:

y = 2x + 2

Step-by-step explanation:

for each rise of 4 in y

there is a run of 2 in x

m = rise/run

m = 4/2

m = 2

when x = 0, y = 2

therefor the y-intercept, b = 2

y = mx + b

y = 2x + 2

8 0

3 years ago

Prove the identity 2csc2x=csc^2xtanz

Verizon [17]

Step-by-step explanation:

Consider the LHS, after the 5th step, consider the RHS

$2 \csc(2x) = \csc {}^{2} (x) \tan(x)$

$2 \frac{1}{ \sin(2x) } = \csc {}^{2} (x) \tan(x)$

$2 \times \frac{1}{2 \sin(x) \cos(x) } = \csc {}^{2} (x) \tan(x)$

$\frac{1}{ \sin(x) \cos(x) } = \csc {}^{2} (x) \tan(x)$

$\csc(x) \sec(x) = \csc {}^{2} (x) \tan(x)$

Consider the RHS

$\csc(x) \sec(x) =( 1 + \cot {}^{2} (x) ( \tan(x))$

$\csc(x) \sec(x) = \tan(x) + \cot(x)$

$\csc(x) \sec(x) = \frac{ \sin(x) }{ \cos(x) } + \frac{ \cos(x) }{ \sin(x) }$

$\csc(x) \sec(x) = \frac{1}{ \sin(x) \cos(x) }$

$\csc(x) \sec(x) = \csc(x) \sec(x)$

7 0

2 years ago

Please help me with this thanks:) fast!!!​

Please help me with this thanks:) fast!!!