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Harlamova29_29 [7]
3 years ago
9

Evaluate the expression 3^4 ÷ (14 − 5) × 2.

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer: 18

Step-by-step explanation: Use PEMDAS

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What is the remainder when 864 is devided by 31? 6 27 4 ther is no remainder
avanturin [10]
Okay. So when you solve 864/31 on a sheet of paper and you divide it properly, the remainder you get should be 27. The answer is B: 27.

6 0
3 years ago
Read 2 more answers
16 POINTS!!! HELP ASAP
nadya68 [22]

Answer:

The answer is 358.01

Step-by-step explanation:

Given:

3\times 10^{2}+5\times 10^{1}+8\times 10^{0}+1\times \frac{1}{10^{2}}

Now, to solve first we crack the power notation then multiply and then do the addition:

3\times 100+5\times 10+8\times 1+1\times \frac{1}{100}

(The value of 10^{1} is 10 and the value of 10^{0} is 1.)

=300+50+8+\frac{1}{100}

=300+50+8+0.01

=358.01.

Therefore, the answer is 358.01 .

7 0
3 years ago
Jana planted 30 tulips. A total of 2/3 of those tulips have bloomed. How many of the tulips that Jana planted have bloomed?
kumpel [21]

20 tulips. 2/3=20/30 when you multiply both the denominator and numerator by 10.

8 0
3 years ago
How does this polynomial identity work on numerical relationships?<br> (y + x) (ax + b)
Serggg [28]

Let us take 'a' in the place of 'y' so the equation becomes

(y+x) (ax+b)

Step-by-step explanation:

<u>Step 1:</u>

(a + x) (ax + b)

<u>Step 2: Proof</u>

Checking polynomial identity.

(ax+b )(x+a) = FOIL

(ax+b)(x+a)

ax^2+a^2x is the First Term in the FOIL

ax^2 + a^2x + bx + ab

(ax+b)(x+a)+bx+ab is the Second Term in the FOIL

Add both expressions together from First and Second Term  

= ax^2 + a^2x + bx + ab

<u>Step 3: Proof </u>

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

Identity is Found .

Trying with numbers now

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)

((10)+8)(7) =(2*25)+(4*5)+(40)+(16)

(18)(7) =(50)+(20)+(56)

126 =126

3 0
3 years ago
A regular octagon rotates 360° about its center. How many times does the image of the octagon coincide with the preimage during
diamong [38]
The number of times the image of the octagon will coincide with the preimage during rotation is determined by:
N = R/C

where
N is the number of times the preimage coincided with the rotated image during rotation
R is the angle of rotation
C is the central angle of the regular polygon

For an octagon, the central angle is
C = 360/8 = 45

So,
N = 360 / 45 = 8

Therefore, the rotated image of the octagon will coincide with the preimage 8 times during rotation.
8 0
3 years ago
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