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Oksi-84 [34.3K]
3 years ago
9

What's the valu of given expression :

="TexFormula1" title=" \sqrt{ 4 \times 4} " alt=" \sqrt{ 4 \times 4} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
sleet_krkn [62]3 years ago
5 0

Answer:

4

Step-by-step explanation:

√ 4 × 4

= √4 × √4

= 2 x 2

= 4

Therefore, 4 is the value of the given expression.

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The graph shows how the length of time a bicycle is rented is related to the rental cost. What is the rate of change shown in th
ANTONII [103]

Answer:

A. 2 (I can't really see the graph clearly, I think this is right)

Step-by-step explanation:

(1,4)(2,6)

6-4 =2

2-1 =1

2/1 =2

5 0
3 years ago
Read 2 more answers
Consider the linear equation x- 3/2y = 2
Allisa [31]

Answer:

don't know

Step-by-step explanation:

not really sure

7 0
3 years ago
Solve the inequality and write the solution in interval notation:<br> k/-12 ≤ 15.
natali 33 [55]
Remember when solving inequalities the sign of your inequality reverses when dividing or multiplying negative values. k/-12<15. k>-180 [-180, positive infinity)
5 0
3 years ago
Segment AB has endpoints on the coordinate grid where A is (- 18, 5) and B is (- 4, 5) Point Z is located exactly 1/8 of the dis
fenix001 [56]

Given:

Endpoints of segment AB are A(- 18, 5) and B(- 4, 5).

Point Z is located exactly 1/8 of the distance from A to B.

To find:

The value of the x-coordinate of point Z.

Solution:

Point Z is located exactly 1/8 of the distance from A to B.

AZ:AB=1:8

AZ:ZB = AZ:(AB-AZ)= 1:(8-1) = 1:7

It means point Z divided segment AB in 1:7.

Using section formula, the x coordinate of point Z is

x-coordinate=\dfrac{mx_2+nx_1}{m+n}

x-coordinate=\dfrac{1(-4)+7(-18)}{1+7}

x-coordinate=\dfrac{-4-126}{8}

x-coordinate=\dfrac{-130}{8}

x-coordinate=-16.25

Therefore, the required x-coordinate of point Z is -16.25.

3 0
3 years ago
The volume of a cone is 37.7 cubic inches, and its height is 4 inches. What is the diameter of the base of the cone?
Rom4ik [11]
Just multiply 37.7 by 4 and get your answer.
6 0
3 years ago
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