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alukav5142 [94]
2 years ago
6

Picasso's Phone Shop charges $65.54 for its activation fee plus $13.10 for every gigabyte, g, of data you use over your limit. T

he equation that
models the total cost (T) is T (g) = 13.10g +65.54 Which value in the equation represents the rate of change?
A
$65.54
B
$78.63
$13.10
the number of gigabytes used over
I don't know yet
4
04.02.05.1289
D
E
Com
5. SE
Mathematics
1 answer:
konstantin123 [22]2 years ago
6 0

Answer:

$13.10 represents the rate of change

Step-by-step explanation:

13.1 is the only value in the equation with a variable (g). There is an additional $13.10 charge for every gigabyte used over the limit, and this is the rate of change.

For example, if 5 gigabytes were used over the limit, the charge would be 13.1(5) or $65.50

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The coordinates of an ordered pair have opposite signs. In which quadrant(s) must the ordered pair lie? Explain.
Alex_Xolod [135]
Alright...so the coordinates of an ordered pair have opposite signs [one sign is positive while the other is negative] so we could have an example of (-x,+y) or (+x,-y) ...that means out of the 4 quadrants these points could be in the 2nd quadrant or the 4th quadrant or corners of the graph

7 0
3 years ago
a fair (6 sided) die is rolled TWO times. What is the probability that the first die is a 2 or the second die is a prime
alexdok [17]

Answer:

The probability that the first die is a 2 or the second die is a prime = 1/12

Step-by-step explanation:

It is given that,a fair (6 sided) die is rolled TWO times.

The sample space for rolling 2 dies

(1, 1), (1, 2) .......... (1,6)

(2,1) ..........................

.

.

(6, 1) ..........................(6, 6)

There are total of 6^2  = 36 sample space

<u>To find the probability</u>

The prime numbers from 1 to 6 are 2, 3 and 5

the  possible outcomes are(2,1), (2, 3) and (2, 5)

The probability that the first die is a 2 or the second die is a prime = 3/36 = 1/12

4 0
3 years ago
2x^(2) + xy + 2y^(2) = 5, (1, 1)<br> (ellipse)
Anvisha [2.4K]
<span>2<span>x2</span>+xy+2<span>y2</span>=5</span>Implicit differentiation yields<span>4x+y+x<span>y′</span>+4y <span>y′</span>=0</span>Solve for <span>y′</span><span>.

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3 0
3 years ago
Write 1-2log7x as a single logarithm
slavikrds [6]

Answer:

log_{7} \frac{7}{x^{2} }

Step-by-step explanation:

We need to write 1 - 2log_{7}x as a single logarithm.

We know that

log_{7}7 = 1

Therefore we have:

log_{7}7 - 2log_{7}x

→ log_{7}7 - log_{7}x^{2}

→ log_{7} \frac{7}{x^{2} }

The solution is: log_{7} \frac{7}{x^{2} }

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The indicated function y1(x is a solution of the given differential equation. use reduction of order or formula (5 in section 4.
Taya2010 [7]
Given a solution y_1(x)=\ln x, we can attempt to find a solution of the form y_2(x)=v(x)y_1(x). We have derivatives

y_2=v\ln x
{y_2}'=v'\ln x+\dfrac vx
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Substituting into the ODE, we get

v''x\ln x+2v'-\dfrac vx+v'\ln x+\dfrac vx=0
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Setting w=v', we end up with the linear ODE

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Multiplying both sides by \ln x, we have

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and noting that

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we can write the ODE as

\dfrac{\mathrm d}{\mathrm dx}\left[wx(\ln x)^2\right]=0

Integrating both sides with respect to x, we get

wx(\ln x)^2=C_1
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Now solve for v:

v'=\dfrac{C_1}{x(\ln x)^2}
v=-\dfrac{C_1}{\ln x}+C_2

So you have

y_2=v\ln x=-C_1+C_2\ln x

and given that y_1=\ln x, the second term in y_2 is already taken into account in the solution set, which means that y_2=1, i.e. any constant solution is in the solution set.
4 0
3 years ago
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