Question

What is mZDAR in circle A?

Answer 1

Answer:

68°

Step-by-step explanation:

Since, angle subtended on the circumference of the circle is half angle subtended on the center of the circle.

$\therefore m\angle DBR = \frac{1}{2} \times m\angle DAR\\\\\therefore 34\degree = \frac{1}{2} \times m\angle DAR\\\\\therefore 34\degree \times 2= m\angle DAR\\\\\therefore 68\degree = m\angle DAR\\\\\therefore m\angle DAR=68\degree$