Given:
Length = x + x + 3 = 2x + 3
Width = 2 + x
Area = length * width
91 ft² = (2x + 3) (2+x)
91 = 4x + 2x² + 6 + 3x
0 = 2x² + 7x + 6 - 91
0 = 2x² + 7x - 85
(2x + 17) ( x - 5)
x = -17/2 or x = 5
Let x = 5 ;
length = 2x + 3 = 2(5) + 3 = 13
width = 2 + x = 2 + 5 = 7
Area = 13 x 7 = 91
Perimeter = 2(length + width)
Perimeter = 2(13 + 7)
Perimeter = 2(20)
Perimeter = 20 feet of fencing
Answer:
624.5 feet
Step-by-step explanation:
Calculation to determine how many feet from the boat is the parasailor
Based on the information given we would make use of Pythagorean theorem to determine how many feet from the boat is the parasailor using this formula
a²+b²=c²
First step is to plug in the formula by substituting the given value
500²+b²=800²
Second step is to evaluate the exponent
250,000+b²=640,000
Third step is to substract 250,000 from both side and simplify
250,000+b²-250,000=640,000-250,000
b²=390,000
Now let determine how many feet from the boat is the parasailor
Parasailor feet=√b²
Parasailor feet=√390,000
Parasailor feet=b=624.49
Parasailor feet=b=624.5 feet (Approximately)
Therefore how many feet from the boat is the parasailor will be 624.5 feet
Answer:
Construct MN.
Since M is the midpoint of OA, OM = MA
Similarly, N is the midpoint of OB.
Thus, ON = NB.
Now, in Δs OMN and OAB,
∠MON = ∠AOB (common angle)
(sides are in proportional ratio; OA = 2OM and OB = 2ON)
∴ Δs OMN and OAB are similar (2 sides are in proportion, with the included angle)
Since they are similar, then ∠OMN = ∠OAB (corresponding angles of similar triangles are equal)
But since ∠OMN = ∠OAB, then that means MN || AB (corresponding angles of two lines must be equal since they also sit relative to the transverse line, OA)
Thus, AB || MN (QED)
Answer:
102°
Step-by-step explanation:
This is an isosceles triangle
x = 180 - 39 - 39
x = 102°
Answer:
Step-by-step explanation:
Let us apply the distributive property to find an equivalent expression for:
For all real numbers a, b, and c, the distributive property says that:
We apply this property to get:
We simplify the RHS to get: