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2 years ago

How many gallons of gas are left after driving 200 miles

1 answer:

8 0

The equation y = -0.04x + 12 gives the number of gallons of gas in your car where x is the number of miles drivene

easy

y=gas left
x=miles

sub 200 for x
y=-0.04(200)+12
y=-8+12
y=4

4 gallons left

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Andrew is selling tickets for the school play, and charges t dollars for adult tickets and 2 dollars for child tickets. On Monda

Andru [333]

Answer:

T=4 plz make brainlest answer

Step-by-step explanation:

Monday overall cost 36+5t

Tuesday overall cost 20+9t

36+5t=20+9t

-20 -20

16+5t =9t

-5t -5t

16=4t

t=4

Check

36+5t=20+9t (t=4)

36+20=20+36

It works

3 0

2 years ago

A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distri

nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{60}{6}= 10$ and the expected value is the same for all the days since that's what we want to test.

now we can calculate the statistic:

$\chi^2 = \frac{(12-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(11-10)^2}{10}+\frac{(10-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(9-10)^2}{10}=0.8$

Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

4 0

2 years ago

Evaluate -5x^2 − 8x + 1 when x = -3.

Yakvenalex [24]

Hello.

Answer: 70

New equation: −5(−3^2)−(8)(−3)+1

How to get the answer:

(−5)(−9)−(8)(−3)+1

=45−(8)(−3)+1

=45−(−24)+1

=69+1

=70

Have a nice day

7 0

2 years ago

A population of amoebas measured at 14000 and grow at the rate of 11%

Dima020 [189]

Answer:

Calculating Growth Rates. The annual percentage growth rate is simply the percent growth divided by N, the number of years. ... The population of Lane County grew 12 percent between 1980 and 1990 or at an rate of 1.2 percent annually.

Step-by-step explanation:

7 0

2 years ago

Factor the polynomial.

Juli2301 [7.4K]

$(4y - 3x)(-y - 3)$ is the factored form of given polynomial $- 4y^2 + 3xy - 12y + 9x$