Answer:
(1.5, -13.5)
Step-by-step explanation:
Midpoint Formula:
Simply plug in our coordinates into the formula:
x = (17 - 14)/2
x = 3/2
y = (-11 - 16)/2
y = -27/2
Which is the solution to the inequality 2 3/5 b-8/15
2 answers:
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The value of a car after 10 years be $20898.27 if the car rental company assumes each car in their fleet depreciates by 6% per year option (a) $20898.27 is correct.
<h3>What is an exponential function?</h3>It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent
where a is a constant and a>1
We can solve this problem by exponential function:
The word depreciate means the price is decreasing.
We can find the value be when the car is 10 years old:
p = 38800(1 - 0.06)¹⁰
p = 38800(0.94)¹⁰
p = 20898.266 ≈ $20898.27
Thus, the value of a car after 10 years be $20898.27 if the car rental company assumes each car in their fleet depreciates by 6% per year option (a) $20898.27 is correct.
Learn more about the exponential function here:
#SPJ1
Answer:
a)
x = -1/√3 = -0.58 is a local maximum
x = 1/√3 = 0.58 is a local minimum
b)
(-1/√3 , 1/√3 ) DECREASING
(-∞, -1/√3) U (1/√3, ∞) INCREASING
Step-by-step explanation:
To answer all of the questions we must obtain the derivative of the fucntion:
If
U(x) = 4(x^3 - x)
then
U'(x) = 4(3x^2 - 1)
U''(x) = 4(3*2 x) = 24 x
U'''(x) = 24
The local maxima and minima of the function U(x) can be found when U'(x) = 0
this occurs when :
3x^2 = 1
that is:
x = ±1/√3
We will know if they are a minimum or a maximum evaluating this points on the second derivative (you can look for it as <u><em>Second derivative test</em></u>), if the result is positive the point corresponds to a minimum and if it is negative it will be a maximum.
Here it is easy to determine wheather is a maximum or a minimum because the second derivative is 24x, therefore if x is negative or positive so the second derivative will be.
a)
x = -1/√3 = -0.58 is a local maximum
x = 1/√3 = 0.58 is a local minimum
b)
the intervals at which the function is increasing { decreasing } is given when the first derivative is positive { negative }
The first derivative will be positive when:
3x^2 > 1
|x| > 1/√3 --> x > 1/√3 and x < -1/√3
The first derivatice will be negative when:
3x^2 < 1
|x| < 1/√3 --> x < 1/√3 and x > -1/√3
Therefore the intervals are:
(-1/√3 , 1/√3 ) DECREASING
(-∞, -1/√3) U (1/√3, ∞) INCREASING
<u><em>** The attached image is a plot of the fucntion where you can see part of the intervals and the local maximum and minimum</em></u>
Answer: Measure of angle E = 45°
Measure of angle D = 45°+5° = 50°
Measure of angle F = 85°
Step-by-step explanation:
Let the measure of angle E be x. ( in degrees)
Then Measure of angle D = x+5
Also, Angle D + Angle E = Angle F +10
Since DEF is a triangle, so the sum of their angles should equal to 180 degrees.
Measure of angle E = 45°
Measure of angle D = 45°+5° = 50°
Measure of angle F = (2(45)-5)° = (90-5)° = 85°