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3 years ago

Terry earns $6.50 per hour babysitting.

Mathematics

1 answer:

Ede4ka [16]3 years ago

3 0

It's c because$6.50h = m h = 4.25

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Help please!!! i need it by 2:00 today. i will give brainliest

MA_775_DIABLO [31]

Answer:

Below in bold.

Step-by-step explanation:

x-intercepts (-3,0) and (6, 0)

y-intercept (0, -5)

Axis of symmetry:

(-3 + 6) / 2 = 1.5

x = 1.5.

Domain = all real x.

Range is f(x) ≥ -6.

Graph is positive for x < -3 and x > 6.

Negative for -3 < x < 6.

Increasing for x > 1.5 and decreasing for x < 1.5.

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3 years ago

Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of

GenaCL600 [577]

Close off the hemisphere $S$ by attaching to it the disk $D$ of radius 3 centered at the origin in the plane $z=0$ . By the divergence theorem, we have

$\displaystyle\iint_{S\cup D}\vec F(x,y,z)\cdot\mathrm d\vec S=\iiint_R\mathrm{div}\vec F(x,y,z)\,\mathrm dV$

where $R$ is the interior of the joined surfaces $S\cup D$ .

Compute the divergence of $\vec F$ :

$\mathrm{div}\vec F(x,y,z)=\dfrac{\partial(xz^2)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial k}=z^2+y^2+x^2$

Compute the integral of the divergence over $R$ . Easily done by converting to cylindrical or spherical coordinates. I'll do the latter:

$\begin{cases}x(\rho,\theta,\varphi)=\rho\cos\theta\sin\varphi\\y(\rho,\theta,\varphi)=\rho\sin\theta\sin\varphi\\z(\rho,\theta,\varphi)=\rho\cos\varphi\end{cases}\implies\begin{cases}x^2+y^2+z^2=\rho^2\\\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi\end{cases}$

So the volume integral is

$\displaystyle\iiint_Rx^2+y^2+z^2\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^3\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{486\pi}5$

From this we need to subtract the contribution of

$\displaystyle\iint_D\vec F(x,y,z)\cdot\mathrm d\vec S$

that is, the integral of $\vec F$ over the disk, oriented downward. Since $z=0$ in $D$ , we have

$\vec F(x,y,0)=\dfrac{y^3}3\,\vec\jmath+y^2\,\vec k$

Parameterize $D$ by

$\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath$

where $0\le u\le 3$ and $0\le v\le2\pi$ . Take the normal vector to be

$\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}=-u\,\vec k$

Then taking the dot product of $\vec F$ with the normal vector gives

$\vec F(x(u,v),y(u,v),0)\cdot(-u\,\vec k)=-y(u,v)^2u=-u^3\sin^2v$

So the contribution of integrating $\vec F$ over $D$ is

$\displaystyle\int_0^{2\pi}\int_0^3-u^3\sin^2v\,\mathrm du\,\mathrm dv=-\frac{81\pi}4$

and the value of the integral we want is

(integral of divergence of F) - (integral over D) = integral over S

==> 486π/5 - (-81π/4) = 2349π/20

5 0

3 years ago

The length of a rectangle is x times the square root of 100. The width is one-half y more than three-halves x. Given that the ar

dimulka [17.4K]

Answer:

$15x^2+5xy-125=0$

Step-by-step explanation:

We are give the following in the question:

Dimensions of rectangle:

Length , l =

$l = x\sqrt{100} = 10x$

Width of rectangle, w =

$w = \dfrac{y}{2} +\dfrac{3x}{2}$

Area of rectangle = 125 square cm.

Area of rectangle =

$A =l\times w$

Putting values, we get,

$125 = 10x\times (\dfrac{y}{2}+\dfrac{3x}{2})\\\\125 = 5xy+15x^2\\15x^2+5xy-125=0$

is the required equation.

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3 years ago

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Find the antiderivative of the function: (x^4+2x^2)/x^3

dangina [55]

Set the function up in integral form and evaluate to find the integral.
F(x)=F(x)=12x2−ln(|x|)−1x2+C

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4 years ago

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I need a answer AS SOON AS POSSIBLE.. thank you :}

nadezda [96]

Answer:

1. c

2. b

3. c

4. a

5. b

6. c

7. c

Step-by-step explanation:

1. to check the congrency normally distance formula is used. if the distances/ length are equal we say that sides are congurent.

2. if the slope of two lines are equal then both the lines are parallel. if the product of the slopes of two lines equal to one then lines will be perpendicular.

3. diagonals bisect or not can be checked by using midpoint formula.

4. equilateral triangle if the distance of each side is equal so, distance formula can be used.

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3 years ago

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