3 years ago

-4x –12 = 48 a.x = 9 b.x = -9 c.x = 15 d.x = -15

Mathematics

1 answer:

Mumz [18]3 years ago

3 0

Answer:

d) x= -15

Step-by-step explanation:

-4x-12=48

1. Add 12 to both sides

-4x-12+12=48+12

2. -4x=60

3. Divide -4 from both sides

Final Answer: x= -15

You might be interested in

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B4%7D%5Calpha-1%5Cfrac%7B1%7D%7B5%7D%3D2%5Cfrac%7B3%7D%7B4%7D" id="TexFormula1

velikii [3]

I DONT KNOW LOL PLS STOP CHEATING

5 0

3 years ago

Amelia pays $24 to rent a boat at the lake for up to six hours she constructs the inequality and number line below to represent

liubo4ka [24]

Money= how many hours
$4= 1h
$8=2h
$12=3h
$16=4h
$20=5h
$24=6h
l hope that helps :)

5 0

3 years ago

Which equation represents the equation of the parabola with focus (-3 3) and directrix y=7?

Artemon [7]

Answer:

The equation $y=\frac{-x^2-6x+31}{8}$ represents the equation of the parabola with focus (-3, 3) and directrix y = 7.

Step-by-step explanation:

To find the equation of the parabola with focus (-3, 3) and directrix y = 7. We start by assuming a general point on the parabola (x, y).

Using the distance formula $d = \sqrt {\left( {x_1 - x_2 } \right)^2 + \left( {y_1 - y_2 } \right)^2 }$ , we find that the distance between (x, y) is

$\sqrt{(x+3)^2+(y-3)^2}$

and the distance between (x, y) and the directrix y = 7 is

$\sqrt{(y-7)^2}$ .

On the parabola, these distances are equal so, we solve for y:

$\sqrt{(x+3)^2+(y-3)^2}=\sqrt{(y-7)^2}\\\\\left(\sqrt{\left(x+3\right)^2+\left(y-3\right)^2}\right)^2=\left(\sqrt{\left(y-7\right)^2}\right)^2\\\\x^2+6x+y^2+18-6y=\left(y-7\right)^2\\\\x^2+6x+y^2+18-6y=y^2-14y+49\\\\y=\frac{-x^2-6x+31}{8}$