Angles ∠ACD and ∠CAB are congruent because they are alternate angles. Then the area of the triangle AOB will be 22.53 square cm.
<h3>What is the
area of the right-angle triangle?</h3>
The area of the right-angle triangle is given as
A = 1/2 x B x H
Where B is the base and H is the height of the right triangle.
We know that angles ∠ACD and ∠CAB are congruent because they are alternate angles.
α₁ = 40°
AO = OC = 7.8 cm
Then the area of the triangle will be
Area = 1/2 x 7.8 x 7.8 x tan40°
Area = 22.53 square cm
More about the area of the right-angle triangle link is given below.
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Answer:
10 servings
Step-by-step explanation:
5 pound= 80 ounce
80/8=10
10
It said "no association between this dude winning and loss in harsh condition"
now look at harsh condition, total is 20, since there is no association that means they are the same, which is 10 and 10
WIN column total is 168, 158 for normal condition, 10 for harsh condition, adds up to 168.
LOSS column total is 72, 62 for normal condition and 10 for harsh condition, adds up to 72.
if u wana check if it adds up with Normal Condition, 62 plus 158 is 220.
checked, complete, this is david signing off
So when you change the mixed numbers into improper fractions, they become 85/4 and 74/4. Your new problem is 85/4-74/4. Basically 85-74. That equals 9. So the improper fraction answer is 9/4. We now make that back into a mixed number, creating 2 1/4, or A.
Answer:
Angle B is 41 degrees
Step-by-step explanation:
1) find the supplement of the 113 degree angle; it is 180-113, or 67, degrees.
2) recognizing that the sum of the interior angles of a triangle is 180 degrees, add up 67 and 72 degrees, obtaining 139 degrees, and subtract this sum from 180 degrees:
180 degrees - 139 degrees = 41 degrees (answer)
The steps are outlined above; the end result is that <B is 41 degrees.
