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baherus [9]
3 years ago
11

what is the equation in slope-intercept form of the line that has a slope of 0.25 and passes through the point (6,-8)

Mathematics
1 answer:
Colt1911 [192]3 years ago
3 0

Answer:

I think this is the correct solution for your question

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Quadrilateral ABCD is rotated 145° about point T. The result is quadrilateral A'B'C'D'. Which congruency statement is correct?
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<span>The congruency statement should be that which shows the congruency of the corresponding angle and the sides. In the rotation of the polygon, the angle A is congruent with angle A' still. The same is true for all the angles and sides. The congruency statement is therefore, ABCD is congruent to A'B'C'D' The answer to this item is letter A. </span>
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3 years ago
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x^2+1/2x+1/16=4/9 Factor the perfect-square trinomial on the left side of the equation. (x + )² = 4/9
Nezavi [6.7K]
The missing number is the square-root of the constant term on the left-hand-side, which equals sqrt(1/16)=1/sqrt(16)=1/4.
Check:
(x+1/4)^2=x^2+2*(1/4)x+(1/4)^2=x^2+x/2+1/16.   ok

Answer: x= 1/4
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Carroll borrowed $500 at 14% interest for 6 months. How much interest did she pay?
pshichka [43]
I think the answer is c
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3 years ago
I will give Brainliest two whoever answers 1st (if correct)
tatuchka [14]

Answer:

It would increase. I am not sure though.

Step-by-step explanation:

Please give me brainliest :)

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2 years ago
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The population of Detroit, Michigan, decreased from 1,027,974 in 1990 to 688,701 in 2013 (Source: U.S. Census Bureau). Find the
AleksandrR [38]

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

to get the slope of any straight line, we simply need two points off of it, so let's use the ones provided in that

\begin{array}{|cc|ll} \cline{1-2} \stackrel{years}{x}&\stackrel{population}{y}\\ \cline{1-2} 1990&1027974\\ 2013&688701\\ \cline{1-2} \end{array}\hspace{5em} (\stackrel{x_1}{1990}~,~\stackrel{y_1}{1027974})\qquad (\stackrel{x_2}{2013}~,~\stackrel{y_2}{688701}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{688701}-\stackrel{y1}{1027974}}}{\underset{run} {\underset{x_2}{2013}-\underset{x_1}{1990}}} \implies \cfrac{-339273}{23}\implies -14751\qquad \stackrel{rate~of}{change}

let's notice, is negative since the population decreased.

5 0
2 years ago
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