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erastova [34]
3 years ago
15

Elena receives ​$131 per year in simple interest from three investments totaling ​$3000. Part is invested at​ 3%, part at​ 4% an

d part at​ 5%. There is ​$1000 more invested at​ 5% than at​ 4%. Find the amount invested at each rate.
The amount invested at​ 3% is ​$___ the amount invested at​ 4% is ​$___ , and the amount invested at​ 5% is ​$___
Mathematics
1 answer:
larisa86 [58]3 years ago
7 0

Answer: Ignore that person he ugly

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GIVING BRAINLIEST how much tens can go in 1,000
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I WILL IVE U 5 STARS
matrenka [14]

Answer:

  A. 1 rectangle, 2 triangles

  B. AB = AE = 5

  C. 36.5 square units

Step-by-step explanation:

<h3>A.</h3>

The attached figure shows 1 rectangle (square) and two triangles.

__

<h3>B.</h3>

These sides are aligned with the grid, so their length is simply the difference in coordinates along the line:

  AB = 2 -(-3) = 5

  AE = 3 -(-2) = 5

__

<h3>C.</h3>

The area of the square is ...

  A = s^2 = 5^2 = 25

The area of triangle BCF is ...

  A = 1/2bh = 1/2(3)(5) = 15/2

The area of triangle CDE is ...

  A = 1/2bh = 1/2(8)(1) = 4

The total area is the sum of the areas of the square and two triangles:

  total area = 25 +7.5 +4 = 36.5 . . . square units

_____

<em>Additional comment</em>

We note that segment CE divides the figure into <em>trapezoid</em> ABCE and <em>triangle</em> CDE. The trapezoid has bases 5 and 8, and height 5, so its area is ...

  A = 1/2(b1 +b2)h = 1/2(5 +8)(5) = 32.5

Triangle CDE has the same area as computed above, 4 square units. So, the total area of the figure is ...

  32.5 +4 = 36. 5 . . . . square units

4 0
3 years ago
Plz solve this question​
Mkey [24]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Simplify ⇨ 1/x(x+a) + 1/x(x-a)

\large \boxed{\mathbb{ANSWER \: WITH \: EXPLANATION} \downarrow}

\sf\frac { 1 } { x ( x + a ) } + \frac { 1 } { x ( x - a ) } \\

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x\left(x+a\right) and x\left(x-a\right) is x\left(x+a\right)\left(x-a\right). Multiply \frac{1}{x\left(x+a\right)} times \frac{x-a}{x-a}. Multiply \frac{1}{x\left(x-a\right)} times \frac{x+a}{x+a}.

\sf\frac{x-a}{x\left(x+a\right)\left(x-a\right)}+\frac{x+a}{x\left(x+a\right)\left(x-a\right)}  \\

Because \frac{x-a}{x\left(x+a\right)\left(x-a\right)} and \frac{x+a}{x\left(x+a\right)\left(x-a\right)} have the same denominator, add them by adding their numerators.

\sf\frac{x-a+x+a}{x\left(x+a\right)\left(x-a\right)}  \\

Combine like terms in x-a+x+a.

\sf\frac{2x}{x\left(x+a\right)\left(x-a\right)}  \\

Cancel out x in both the numerator and denominator.

\sf\frac{2}{\left(x+a\right)\left(x-a\right)}  \\

Expand \left(x+a\right)\left(x-a\right).

\boxed{\boxed{ \bf\frac{2}{x^{2}-a^{2}}}}  \\

3 0
3 years ago
Hey can someone help with this question
egoroff_w [7]

Answer:

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Step-by-step explanation:

  • Population = 10 511 215
  • Area = 8 723 square miles

<u>Population density is the number of people per unit of area:</u>

  • 10511215 / 8 723 = 1205 people per square miles

8 0
3 years ago
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