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Answer:
The equation of line passing through point (2 , 2) and perpendicular to line y = x is y = - x + 4 .
Step-by-step explanation:
Given as :
The line equation is y = x
Now, equation of line in slope-intercept form y = m x + c
where m is the slope of line and c is y-intercept
Comparing given line equation with standard line equation
The slope of line y = x is m = 1
Again
Other line is passing through point (2 ,2) and is perpendicular to line y = x
Let The slope of other line = M
∵ From perpendicular lines property
Product of slope of lines = - 1
i.e m × M = - 1
Or , M =
Or, M =
∴ M = - 1
<u>Now, Equation of other line in point-slope form</u>
The other line is passing through point (2 , 2) and slope M = - 1
So, y - = M × (x -
)
Or, y - 2 = - 1 × ( x - 2 )
Or, y - 2 = - x + 2
Or, y = - x + 2 + 2
Or, y = - x + 4
Hence, The equation of line passing through point (2 , 2) and perpendicular to line y = x is y = - x + 4 . Answer
Step-by-step explanation:
that's for Part B
Part C: triangles PQR and P"Q"R" are not congruent since the corresponding sides are not equal
