Assuming that the units are in cm
Given,
Diameter of the cone = 12 cm
Using the above, the radius of the cone can be determined, which is half the diameter of the cone
∴ Radius of the cone (r) = 12/2 = 6 cm
Height of the cone (h) = 7 cm
Using the above, slant height (s) = √(r² + h²) = √(6² + 7²) = √36 + 49 = √85 = 9.22 cm
π = 3.14
Now using the above values, we can calculate the total surface area of the cone.
Total surface area of the cone (A) = Lateral surface area of the cone (L) + Base surface area of the cone (B)
Lateral surface area of the cone (L) = π r s = 3.14 x 6 x 9.22 = 173.70 cm²
Base surface area of the cone (B) = π r² = 3.14 x 6² = 113.04 cm²
Total surface area of the cone = L + B = 173.70 + 113.04 = 286.74 cm²
Answer:
76
2 real solutions
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Standard Form: ax² + bx + c = 0
Discriminant: b² - 4ac
- Positive - 2 solutions
- Equal to 0 - 1 solution
- Negative - No solutions/Imaginary
Step-by-step explanation:
<u>Step 1: Define</u>
x² - 6x - 10 = 0
<u>Step 2: Identify Variables</u>
<em>Compare quadratic.</em>
x² - 6x - 10 = 0 ↔ ax² + bx + c = 0
a = 1, b = -6, c = -10
<u>Step 3: Find Discriminant</u>
- Substitute in variables [Discriminant]: (-6)² - 4(1)(-10)
- [Discriminant] Evaluate exponents: 36 - 4(1)(-10)
- [Discriminant] Multiply: 36 + 40
- [Discriminant] Add: 76
This tells us that our quadratic has 2 real solutions.
Answer:
SA = 251.33 yd ^2
V = 301.59 yd ^3
Step-by-step explanation:
Right cylinder 2π = 6.28318530718
Solve for surface area
A =2πrh+2πr2 = 24 x 2π + 2π x 16
A =150.796447372 + 100.530964915
A ≈251.33 yd^2
Right cylinder π = 3.14159265359
Solve for volume
V = πr2h = 16 x 6 = 96π
V = 3.14159265359 x 96
V = 301.592894745
V= 301.59 yd ^3
Yes both equations are equal because when you do distributive property it is the same
Answer:
they need 4 buses
60+60+60=180 that does not get you to 196 so you would add 1 more bus
which equals 4 buses
