we need to find 1% of 10000 first
so we divide 10000:100= 100 (that's 1%)
to find the 60% which will be accepted we multiply 100 × 60 = 6000 students accepted
of those 6000 we need to find 50% which is ½ so we basically just divide by 2, aka 6000 : 2 = 3000 people which will be enrolled
The required probability of the coin landing tails up at least two times is 15/16.
Given that,
A fair coin is flipped seven times. what is the probability of the coin landing tails up at least two times is to be determined.
<h3>What is probability?</h3>
Probability can be defined as the ratio of favorable outcomes to the total number of events.
Here,
In the given question,
let's approach inverse operation,
The probability of all tails = 1 / 2^7 because there is only one way to flip these coins and get no heads.
The probability of getting 1 head = 7 /2^7
Adding both the probability = 8 / 2^7
Probability of the coin landing tails up at least two times = 1 - 8/2^7
= 1 - 8 / 128
= 120 / 128
= 15 / 16
Thus, the required probability of the coin landing tails up at least two times is 15/16.
Learn more about probability here:
brainly.com/question/14290572
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4 big mice and 3 small mice because 4 X 25=100; 3 X 10=30
100+30=130
is that right?
Answer:
50.5 m^3
Step-by-step explanation:
Volume of pyramid = 1/3 × base area × height.
- Height: 11
- Base Dimensions: 4.3 and 3.2
Area of Base:
Next, we multiply 13.76 by 11.
Lastly, divide by 3 and round to nearest tenth.
- 151.36 ÷ 3
- 50.453333..
- ≈ 50.5
Therefore, the answer is 50.5 m^3
Answer:
weak negative
Step-by-step explanation:
because its in negative and its in the thousands place.
