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aev [14]
3 years ago
12

What is the length of the hypotenuse of right UVW shown?

Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0

Answer:

UV

Step-by-step explanation:

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krek1111 [17]

Answer:

\displaystyle x = \frac{25\sqrt{2}}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Trigonometry</u>

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] cosθ = adjacent over hypotenuse

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

Angle θ = 45°

Adjacent Leg = 25

Hypotenuse = <em>x</em>

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in variables [cosine]:                                                                   \displaystyle cos(45^\circ) = \frac{x}{25}
  2. [Multiplication Property of Equality] Multiply 25 on both sides:                 \displaystyle 25cos(45^\circ) = x
  3. Rewrite:                                                                                                         \displaystyle x = 25cos(45^\circ)
  4. Evaluate:                                                                                                         \displaystyle x = \frac{25\sqrt{2}}{2}
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