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3 years ago

11

Write down step by step the process that you use to solve multiplying a fraction by an integer.

1 answer:

Marta_Voda [28]3 years ago

3 0

Answer:

you place the 1 under the integer and follow the steps keep change it flip it . SO basically you keep the integer and the 1 and you change the sign to division and you place the numerator where the denominator is and the denominator goes where the numerator is.

Step-by-step explanation:

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Find the slope given the following information <br> (3,7) and (-4,10)

hram777 [196]

Answer:

m=-3/7

Step-by-step explanation:

m=rise/run=Δy/Δx

m=y2−y1/x2−x1

m=10−7/−4−3

m=3/−7

m=−3/7

6 0

2 years ago

Find the surface area of a square pyramid with a base length of 24 cm and a height of 16 cm. Explain how you solved the problem.

icang [17]

Answer:

the answer b

Step-by-step explanation:

[surface area]=[area of 4 triangles sides]+[area of square base]

[area of square base]=24*24--------> 576 cm²

[area of one triangles side]

l=slant height

l²=16²+12²-------> l²=400-----------> l=20 cm

[area of one triangles side]=24*20/2--------> 240 cm²

[area of 4 triangles sides]=4*240----------> 960 cm²

[surface area]=[960]+[576]--------> 1536 cm²

6 0

3 years ago

OLEGan [10]

Answer:

∴ ∠BAD = $sin^{-1}$ (0.2044) = 11.8°

Step-by-step explanation:

i) AD = 9 cm

ii) DC = 3 cm

iii) ∠BCD = 35°

iv) Since AB is parallel to DC and ∠ABD = 90° then we can conclude that ∠BDC = 90°.

v) $\frac{BD}{DC} = \frac{BD}{3\hspace{0.1cm}cm} = tan(35)$ = 0.6128 ∴ BD = 3 $\times$ 0.6128 = 1.84 cm

vi) ∴ sin(∠ BAD ) = $\frac{BD}{AD}$ ⇒ sin(∠ BAD ) = $\frac{1.84}{9}$ = 0.2044

∴ ∠BAD = $sin^{-1}$ (0.2044) = 11.8°

7 0

4 years ago

Write two polynomials whose sum is x to the second power and whose difference is 1

Alex777 [14]

Answer:

Therefore, the first polynomial is:

$Z=\frac{1}{2}x^2+\frac{1}{2}\\$

the second polynomial is:

$Y=\frac{1}{2}x^2-\frac{1}{2}\\$

Step-by-step explanation:

We assume that: Z is first polynomial and Y is second polynomial.

Therefore, we have

$Z+Y=x^2\\\\Z-Y=1\\\\\implies Z+Y+Z-Y=x^2+1\\\\2Z=x^2+1\\\\Z=\frac{1}{2}x^2+\frac{1}{2}\\$

now, we get

$\implies Z+Y-Z+Y=x^2-1\\\\2Y=x^2-1\\\\Y=\frac{1}{2}x^2 -\frac{1}{2}$

Therefore, the first polynomial is:

$Z=\frac{1}{2}x^2+\frac{1}{2}\\$

the second polynomial is:

$Y=\frac{1}{2}x^2-\frac{1}{2}\\$

6 0

3 years ago

Determined to finish her milkshake before Diego, Lin now drinks her

antoniya [11.8K]

Answer:the graph tells you 24 seconds by 4 ounces

Step-by-step explanation:

5 0

3 years ago