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leonid [27]
3 years ago
11

Write down step by step the process that you use to solve multiplying a fraction by an integer.

Mathematics
1 answer:
Marta_Voda [28]3 years ago
3 0

Answer:

you place the 1 under the integer and follow the steps keep change it flip it . SO basically you keep the integer and the 1 and you change the sign to division and you place the numerator where the denominator is and the  denominator goes where the numerator is.

Step-by-step explanation:

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A stock was purchased at $15.75 per share, and sold at $19.25 per share.
BARSIC [14]
ANSWER:
B. $3.50


STEP BY STEP EXPLANATION:

We start out with buying the stock for $15.75 then sell it at $19.25. We need to find the difference.

Subtract $15.75 from $19.25

19.25 - 15.75 = 3.50

To check your work add $3.50 to $15.75

15.75 + 3.50 = 19.25


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3 0
3 years ago
83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi
arlik [135]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

Step-by-step explanation:

Information given

\bar X=32.1 represent the sample mean

\mu population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom given by:

df=n-1=8-1=7

The confidence level is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,82)" "=CHISQ.INV(0.95,82)". so for this case the critical values are:

\chi^2_{\alpha/2}=104.139

\chi^2_{1- \alpha/2}=62.132

The confidence interval is given by:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

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3 years ago
Edgar and Rebekah are surveying their neighbors about the community pool. Their questions, written on the survey, are below: Edg
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